
By: pillai (offline) Monday, September 19 2011 @ 03:20 AM CDT (Read 1069 times)



pillai 
There were some marbles in Boxes A, B & C. Box A contains 60% of total marbles in Boxes B & C. Box B contains 25% of the total no. of marbles in Boxes A & C. There were 4 more marbles in Box C than Box A. Find the total no. of marbles in all the Boxes.

Newbie
Registered: 02/19/10 Posts: 4





By: pkrdd (offline) Monday, September 19 2011 @ 03:57 AM CDT



pkrdd 
You have to use constant total approach to solve this problem.
Part 1:
Box B + Box C = 100%
Box A = 60 %
Ratio of Total (B+C): Total A = 100:60 = 5:3 (simplest form)
Total units of Boxes A+B+C = 8units
Part 2:
Box A + Box C = 100%
Box B = 25%
Ratio of Total (A+C): Total B = 100:25 = 4:1 (simplest form)
Total units of Boxes A+B+C = 5units
Now make the total units same by multiplying part 1 with 5 & Part 2 with 8
New units derived are as follows
Total (B+C) = 25u
Total A = 15u
Total (A+C):= 32u
Total B = 8u
Total units of Boxes A+B+C = 40u = 15u+ 8u + Total C
Total C = 17u
Given that Box C has 4 more marbles than Box A
ie., 17u  15u = 4
2u = 4
u = 2
Total number of marbles in all 3 boxes altogether = 40u = 40 *2 = 80
Ans = 80

Junior
Registered: 01/11/10 Posts: 16





By: pillai (offline) Wednesday, September 21 2011 @ 09:35 PM CDT



pillai 
pkrdd, thanks so much for your help

Newbie
Registered: 02/19/10 Posts: 4



