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Thursday, March 23 2017 @ 05:17 AM CDT
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 Need help in P5 RGS 2010 Paper 2 Qn 28
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By: apangns (offline)  Monday, September 26 2011 @ 11:15 PM CDT (Read 1069 times)  
apangns

Can someone help in P5 RGS 2010 Paper 2 Qn 28

Thanks

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By: GIM (offline)  Wednesday, September 28 2011 @ 11:31 PM CDT  
GIM

Since Triangle PYX and triangle YRT are along line PYR, therefore

YT 4
---- = ----
PX 10

then, TR 4
----- = -----
XY 10

we know TR = 9 cm

9 4
----- = ------
XY 10

Cross multiply : 4 x XY = 9 x 10
XY = 90 / 4 = 22.5 cm

Area of rectangle XYTS = 22.5 x 4 = 90 cm square

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By: GIM (offline)  Wednesday, September 28 2011 @ 11:45 PM CDT  
GIM

Sorry for the error, the numbers are all jumbled when I submitted.

Since triangle PYX and Triangle YRT are along line PYR, therefore

YT : PX, then
4 : 10

TR : XY is also
4 : 10

TR/XY = 4/10

We know TR is 9cm

XY = (9 x10) / 4 = 22.5cm

Area of rect = 22.5 x 4 = 90 cm sq

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By: hassanalsg (offline)  Friday, September 30 2011 @ 10:16 PM CDT  
hassanalsg

hello all. But im not sure P5 has been taught similar triangles property. or are we using ratio here?

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By: apangns (offline)  Saturday, October 01 2011 @ 01:00 AM CDT  
apangns

Thanks GIM for your help. Smile

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