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 By: veronica2566 (offline)  Thursday, October 06 2011 @ 07:39 PM CDT (Read 2431 times)
veronica2566

Appreciate if anyone can help :

1) Mr Yusof had a total of 328 blue and green pens in his bookshop. He sold 1/5 of his blue pens and bought another 47 green pens. After that, the number of green pens he had was 5/8 the number of blue pens. How many more blue pens than green pens did Mr Yusof have at first?

2) Mr Raziq spent a total of \$63.80 on some badges and bookmarks. The number of badges he bought was twice the number of bookmarks. He paid \$2.20 more for all the badges. If each bookmark cost \$1.30 more than a badge, how many bookmarks did he buy?

3) A class of 42 pupils borrowed an average of 5 books, There are twice as many boys as girls in the class. The average number of books borrowed by the boys was 4. What was the average number of books borrowed by the girls?

4) Mr Tan placed some poles at 0.5m apart equally around his circular garden. The 5th pole as facing directly opposite the 14th pole. What was the perimater of the garden?

Thanks!

Junior

Registered: 06/23/10
Posts: 24

 By: RachelAng (offline)  Thursday, October 06 2011 @ 10:57 PM CDT
RachelAng

3) A class of 42 pupils borrowed an average of 5 books, There are twice as many boys as girls in the class. The average number of books borrowed by the boys was 4. What was the average number of books borrowed by the girls?

3 units = 42 pupils
1 unit = 14 pupils
No. of girls in the class = 14.
No. of boys in the class = 28.

Total no. of books borrowed by class = 42 x 5 = 210.
No. of books borrowed by boys = 28 x 4 = 112.
No. of books borrowed by girls = 210 - 112 = 98
Average no. of books borrowed by girls = 98 / 14 = 7 (ANS)

4) Mr Tan placed some poles at 0.5m apart equally around his circular garden. The 5th pole as facing directly opposite the 14th pole. What was the perimater of the garden?

Pole 5 matches with Pole 14. Draw out in a circle and you get total 18 poles.
Distance between each pole is 0.5m.
Total no. of gaps = 18.
So perimeter of garden = 18 x 0.5 = 9m

Newbie

Registered: 01/23/11
Posts: 4

 By: GIM (offline)  Friday, October 07 2011 @ 09:40 AM CDT
GIM

1. Mr Yusof had a total of 328 blue and green pens in his bookshop. He sold 1/5 of his blue pens and bought another 47 green pens. After that, the number of green pens he had was 5/8 the number of blue pens. How many more blue pens than green pens did Mr Yusof have at first?

Total blue & green pens = 328

Blue sold :1/5
Blue left : 1 - 1/5 = 4/5 = 8/10
Total blue was 10 units
Remaining blue is 8 units

Bought 47 green pens
Now green pens is 5/8 of blue pens
Green becomes 5 units

5 units of green + 10 units of blue ------ 328 + 47=375
15 units ------- 375
1 unit------------ 375 /15 = 25

Total blue------ 10u x 25 = 250 pens
Total green --- 328 - 250 = 78

Difference = 250 - 78 = 172 more blue pens

Regular Member

Registered: 11/07/10
Posts: 70

 By: veronica2566 (offline)  Saturday, October 08 2011 @ 12:24 AM CDT
veronica2566

Junior

Registered: 06/23/10
Posts: 24

 By: qmzhou87 (offline)  Monday, October 10 2011 @ 03:57 AM CDT
qmzhou87

2) Mr Raziq spent a total of \$63.80 on some badges and bookmarks. The number of badges he bought was twice the number of bookmarks. He paid \$2.20 more for all the badges. If each bookmark cost \$1.30 more than a badge, how many bookmarks did he buy?

63.8-2.2=61.6
61.6/2=30.8
He spent \$30.8 on bookmark and \$33 on bdages
\$33/2=\$16.5 He use this amount of money to buy half number of total badges, which is the same number of bookmarks he bought
\$30.8-\$16.5=\$14.3
\$14.3/1.3=11
He bought 11 bookmarks and 22 badges.
\$33/22=\$1.5 per bagde
\$1.5+\$1.3=\$2.8 per bookmark, \$2.8*11=\$30.8

Newbie

Registered: 10/09/11
Posts: 2

 By: DEVBALAJI (offline)  Wednesday, October 19 2011 @ 11:44 AM CDT
DEVBALAJI

I believe there is a mistake in gmzhou87's solution. The amount of money he spent on the bookmarks is not the same as the amount spent on half of the badges as each bookmark costs \$1.30 more than a badge.

My solution is as following:

\$63.80 - (\$2.20 x 3) = \$57.20 (excessive \$1.30s)
\$57.20 / \$1.30 = 44 bookmarks

Newbie

Registered: 12/31/06
Posts: 4

 By: nisalam (offline)  Thursday, October 20 2011 @ 09:20 PM CDT
nisalam

I tend to agree with gmzhou. He never said that the amount spent on half the badges was the same as that on the bookmarks, only that the \$30.80 paid for the bookmarks got him the same number of bookmarks as \$16.50 on badges. Hence the difference between these sums divided by the unit difference (\$1.30) indicates how many bookmarks there were (and by doubling, the number of badges).

Junior

Registered: 04/29/10
Posts: 30

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