Welcome to Test-paper.info
Thursday, January 18 2018 @ 03:50 PM CST
 Select a Forum » General Chat » Primary 1 Matters » Primary 2 Matters » Primary 3 Matters » Primary 4 Matters » Primary 5 Matters » Primary 6 Matters » Question, Feedback and Comments » Education Classified
 Forum Index >  Test Paper Related >  Primary 4 Matters Maths
 | Printable Version
 By: achieve_goal (offline)  Thursday, October 27 2011 @ 04:35 AM CDT (Read 1066 times)
achieve_goal

Jane and Mary had a sum of money. Mary gave 1/3 of her money to Jane.

Then, Jane gave 1/3 of what she had to Mary. In the end Mary had \$48 while

Jane had \$64. How much money did Mary have at first?

Regular Member

Registered: 09/14/11
Posts: 102

 By: sokechan (offline)  Friday, October 28 2011 @ 02:49 AM CDT
sokechan

M -> 3 Units
J -> ?

M gave J 1 Unit

M -> 2 Units
J -> ? + 1 Unit

M -> 2 Units
J -> ? + 1 Unit

J gave M 1 Part

M -> 2 Units + 1 Part
J -> 2 Parts + 1 Unit

2u + 1p = 48
1u + 2p = 64
---------------------
3u + 3p = 112
---------------------
1u + 1p = 37 1/3
---------------------
1u = 10 2/3
3u = 32

Junior

Registered: 02/25/11
Posts: 23

 By: Kevin1991 (offline)  Friday, October 28 2011 @ 01:53 PM CDT
Kevin1991

I think that there might be a mistake in sokechan answer.

Here is my working:

After Jane gave 1/3 of her money, she would have 2/3 left.

Therefore,
2/3 of Jane(Final) = \$64
1/3 of Jane(Final) = 64/2
= \$32

This means Jane gave \$32 to Mary.

Thus,
2/3 of Mary(Initially) = 48 - 32
= 16

3/3 of Mary(Initially) = 16/2 x 3
= 24

Mary has \$24 initially.

Newbie

Registered: 10/09/11
Posts: 3

 By: achieve_goal (offline)  Saturday, October 29 2011 @ 02:33 AM CDT
achieve_goal

Thanks!

Regular Member

Registered: 09/14/11
Posts: 102

 All times are CST. The time is now 03:50 pm.
 Normal Topic Locked Topic Sticky Topic
 New Post Sticky Topic w/ New Post Locked Topic w/ New Post
 View Anonymous Posts Able to Post HTML Allowed Censored Content