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By: achieve_goal (offline)  Thursday, October 27 2011 @ 04:35 AM CDT (Read 1000 times)  
achieve_goal

Jane and Mary had a sum of money. Mary gave 1/3 of her money to Jane.

Then, Jane gave 1/3 of what she had to Mary. In the end Mary had $48 while

Jane had $64. How much money did Mary have at first?



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By: sokechan (offline)  Friday, October 28 2011 @ 02:49 AM CDT  
sokechan

M -> 3 Units
J -> ?

M gave J 1 Unit

M -> 2 Units
J -> ? + 1 Unit

M -> 2 Units
J -> ? + 1 Unit

J gave M 1 Part

M -> 2 Units + 1 Part
J -> 2 Parts + 1 Unit

2u + 1p = 48
1u + 2p = 64
---------------------
3u + 3p = 112
---------------------
1u + 1p = 37 1/3
---------------------
1u = 10 2/3
3u = 32

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By: Kevin1991 (offline)  Friday, October 28 2011 @ 01:53 PM CDT  
Kevin1991

I think that there might be a mistake in sokechan answer.

Here is my working:

After Jane gave 1/3 of her money, she would have 2/3 left.

Therefore,
2/3 of Jane(Final) = $64
1/3 of Jane(Final) = 64/2
= $32

This means Jane gave $32 to Mary.

Thus,
2/3 of Mary(Initially) = 48 - 32
= 16

3/3 of Mary(Initially) = 16/2 x 3
= 24

Mary has $24 initially.

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By: achieve_goal (offline)  Saturday, October 29 2011 @ 02:33 AM CDT  
achieve_goal

Thanks! Mr. Green

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