
By: achieve_goal (offline) Thursday, October 27 2011 @ 04:35 AM CDT (Read 1000 times)



achieve_goal 
Jane and Mary had a sum of money. Mary gave 1/3 of her money to Jane.
Then, Jane gave 1/3 of what she had to Mary. In the end Mary had $48 while
Jane had $64. How much money did Mary have at first?

Regular Member
Registered: 09/14/11 Posts: 102





By: sokechan (offline) Friday, October 28 2011 @ 02:49 AM CDT



sokechan 
M > 3 Units
J > ?
M gave J 1 Unit
M > 2 Units
J > ? + 1 Unit
M > 2 Units
J > ? + 1 Unit
J gave M 1 Part
M > 2 Units + 1 Part
J > 2 Parts + 1 Unit
2u + 1p = 48
1u + 2p = 64

3u + 3p = 112

1u + 1p = 37 1/3

1u = 10 2/3
3u = 32

Junior
Registered: 02/25/11 Posts: 23





By: Kevin1991 (offline) Friday, October 28 2011 @ 01:53 PM CDT



Kevin1991 
I think that there might be a mistake in sokechan answer.
Here is my working:
After Jane gave 1/3 of her money, she would have 2/3 left.
Therefore,
2/3 of Jane(Final) = $64
1/3 of Jane(Final) = 64/2
= $32
This means Jane gave $32 to Mary.
Thus,
2/3 of Mary(Initially) = 48  32
= 16
3/3 of Mary(Initially) = 16/2 x 3
= 24
Mary has $24 initially.

Newbie
Registered: 10/09/11 Posts: 3





By: achieve_goal (offline) Saturday, October 29 2011 @ 02:33 AM CDT



achieve_goal 
Thanks!

Regular Member
Registered: 09/14/11 Posts: 102



