
By: Achiever (offline) Thursday, February 16 2012 @ 12:50 AM CST (Read 1354 times)



Achiever 
Anyone can solve these problems?
1. Bala bought a watch for $315. He paid the cashier in $10 and $5 notes.
If there were 41 dollar notes altogether, how many $5 notes were there?
2. Miss Ang buys some sweets. If she gives 3 sweets to each pupil, she will have 12 sweets left.
If she gives 4 sweets to each pupil, she will need 24 sweets more.
a) How many pupils are there?
b) How many sweets does she have?
3. If Wanwan gives Jingjing $24, they will have the same amount of money.
If Jingjing gives Wanwan $24, Wanwan’s money will be 9 times as much as that of Jingjing’s remaining money.
How much does Wanwan have at first?
4. 3 similar staplers and 4 similar holepunchers cost $36.
1 similar stapler and 3 such holepunchers cost $22.
Find the cost of 1 stapler?

Newbie
Registered: 02/15/12 Posts: 9





By: achieve_goal (offline) Thursday, February 16 2012 @ 06:22 AM CST



achieve_goal 
Q1. The answer is:
$10 notes: 22x10=220
$5 notes: 19x5=95
22+19=41 dollar notes
$220+$95=$315
Ans: 22 ten dollar notes
19 five dollar notes

Regular Member
Registered: 09/14/11 Posts: 102





By: awyw1201 (offline) Thursday, February 16 2012 @ 06:50 AM CST



awyw1201 
1) suppose all 41 notes are $5 notes
41x 5=205
315205=110(diff)
105=5(diff btw one $10 and one $5)
110/5=22 (no. of $10 notes)
4122=19
Ans: 19 $5 notes
2)
a)let the no. of children be 1u.
3u + 12= 4u  24
1u= 36
b) 3 x 36 + 12= 120
Ans:a) 36 pupils. b) 120 sweets
3) W gives $24 to JW has $48 more than J at first
J gives $24 to W W has 9 times as much as J
8 u= 24 + 48 + 24 = 96
1u = 12
12 + 24 + 48 = 84
Ans: $84
4) 3S + 4H = 36(1)
1S + 3H = 22(2)
(2) x 33S + 9H = 66(3)
Compare (1) and (3), we have
5H = 30
1H= 6
3H=18
Sub that into (2), we get
1S=2218= 4
Ans: $4

Regular Member
Registered: 07/08/11 Posts: 87





By: Achiever (offline) Thursday, February 16 2012 @ 07:15 PM CST



Achiever 
Thanking your for helping to solve

Newbie
Registered: 02/15/12 Posts: 9



