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By: wwk1211 (offline)  Wednesday, March 07 2012 @ 12:11 PM CST (Read 820 times)  
wwk1211

Can anybody kindly help me to solve this problem?

Thank you.

Sam bought 3 Chinese books and 3 English books for $37.50. Gordan bought 1
Chinese book and 2 English books for $21. Find the cost of 1 Chinese book and the
cost of 1 English book.

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By: cymphere (offline)  Wednesday, March 07 2012 @ 09:00 PM CST  
cymphere

Quote by: wwk1211

Can anybody kindly help me to solve this problem?

Thank you.

Sam bought 3 Chinese books and 3 English books for $37.50. Gordan bought 1
Chinese book and 2 English books for $21. Find the cost of 1 Chinese book and the
cost of 1 English book.



Hi,I am able to help as below:
3C + 3E = $37.50

1C (x3) + 2E (x3) = $21 (x3) this is to get rid of C first
3C + 6E = $63

3C - 3C, so C no longer exist
6E - 3E = $63-$37.50
3E = $25.50
E = $25.50 / 3
= $8.50 (1 English book cost $8.50)
1 E = $8.50
1C + 2 (x8.50) = $21
1C + 17 = $21
1C = $21-17
C =$4/1
C =$4 (1 Chinese book cost $4)

I hope you will understand.

Rgds
Cymphere

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