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 By: wwk1211 (offline)  Wednesday, March 07 2012 @ 12:11 PM CST (Read 846 times)
wwk1211

Can anybody kindly help me to solve this problem?

Thank you.

Sam bought 3 Chinese books and 3 English books for \$37.50. Gordan bought 1
Chinese book and 2 English books for \$21. Find the cost of 1 Chinese book and the
cost of 1 English book.

Newbie

Registered: 03/07/12
Posts: 3

 By: cymphere (offline)  Wednesday, March 07 2012 @ 09:00 PM CST
cymphere

Quote by: wwk1211

Can anybody kindly help me to solve this problem?

Thank you.

Sam bought 3 Chinese books and 3 English books for \$37.50. Gordan bought 1
Chinese book and 2 English books for \$21. Find the cost of 1 Chinese book and the
cost of 1 English book.

Hi,I am able to help as below:
3C + 3E = \$37.50

1C (x3) + 2E (x3) = \$21 (x3) this is to get rid of C first
3C + 6E = \$63

3C - 3C, so C no longer exist
6E - 3E = \$63-\$37.50
3E = \$25.50
E = \$25.50 / 3
= \$8.50 (1 English book cost \$8.50)
1 E = \$8.50
1C + 2 (x8.50) = \$21
1C + 17 = \$21
1C = \$21-17
C =\$4/1
C =\$4 (1 Chinese book cost \$4)

I hope you will understand.

Rgds
Cymphere

Newbie

Registered: 09/16/10
Posts: 1

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