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 Pri 5 problem sum
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By: jennefer_06 (offline)  Saturday, March 24 2012 @ 01:55 PM CDT (Read 1186 times)  
jennefer_06

I can do this with algebra. But I can't seem to solve it without algebra.

Henry and David have a ratio of 13:8. When each of them receives $133 each. Henry have 4 times as much as David. How much does Henry have at first?


Pls help! Frown

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By: echeewh (offline)  Sunday, March 25 2012 @ 09:07 PM CDT  
echeewh

Hey Jennifer,

Apply the Constant Difference concept - Difference Before is same as After

<Before>
H : D Diff
13 : 8 5

<After>
4 : 1 3

Hence, we need to multiply <Before> ratio by 3x; <After> ratio by 5x.

<Before>

H : D Diff
39 : 24 15

<After>
20 : 5 15

Notice that there is now a decrease of 19 units from each of H and D. ( I think there is some typo in your question - instead of each of them receiving $133 each, it should be giving away $133 each ).

So...

19u --> 133
1u --> 7

H (at first) = 39u --> 39 x 7
= $273
=============================

Do let me know again if this answer doesnt match your answer / answerkey.

Cheers

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By: jennefer_06 (offline)  Wednesday, April 11 2012 @ 11:09 AM CDT  
jennefer_06

Yes! I do think the question is wrong. Because it gave me a negative answer when I do it with algebra. Thanks for ur help Smile

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