
By: jennefer_06 (offline) Saturday, March 24 2012 @ 01:55 PM CDT (Read 1249 times)



jennefer_06 
I can do this with algebra. But I can't seem to solve it without algebra.
Henry and David have a ratio of 13:8. When each of them receives $133 each. Henry have 4 times as much as David. How much does Henry have at first?
Pls help!

Newbie
Registered: 03/19/12 Posts: 3





By: echeewh (offline) Sunday, March 25 2012 @ 09:07 PM CDT



echeewh 
Hey Jennifer,
Apply the Constant Difference concept  Difference Before is same as After
<Before>
H : D Diff
13 : 8 5
<After>
4 : 1 3
Hence, we need to multiply <Before> ratio by 3x; <After> ratio by 5x.
<Before>
H : D Diff
39 : 24 15
<After>
20 : 5 15
Notice that there is now a decrease of 19 units from each of H and D. ( I think there is some typo in your question  instead of each of them receiving $133 each, it should be giving away $133 each ).
So...
19u > 133
1u > 7
H (at first) = 39u > 39 x 7
= $273
=============================
Do let me know again if this answer doesnt match your answer / answerkey.
Cheers

Active Member
Registered: 04/21/11 Posts: 627





By: jennefer_06 (offline) Wednesday, April 11 2012 @ 11:09 AM CDT



jennefer_06 
Yes! I do think the question is wrong. Because it gave me a negative answer when I do it with algebra. Thanks for ur help

Newbie
Registered: 03/19/12 Posts: 3



