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Friday, August 18 2017 @ 03:53 AM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 RGPS SA1 2011 Q14 Maths
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By: benrit (offline)  Friday, April 13 2012 @ 09:39 PM CDT (Read 1739 times)  
benrit

Hi,

would appreciate any help with Question 14 please ?

Thanks in advance
Ben

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By: echeewh (offline)  Saturday, April 14 2012 @ 06:43 AM CDT  
echeewh

Hi there,

Solution is provided as follows:

Since XSR and PXQ have a common base of SR ( = PQ ), we have ...

XSR + PXQ = ( SR / 2 ) x ( sum of respective heights of XSR, PXQ )
= ( SR x PS ) / 2
= ( Area of Rectangle PQRS ) / 2
= 122.25 + 144.5
= 266.75

Area of XSQ = PQS - PXS - PXQ
= [ ( Area of Rectangle PQRS ) / 2 ] - 44.14 - 144.5
= 266.75 - 188 .64
= 78.11 cm2

===========================================================

Hope this helps.

Best regards,
Edward

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