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By: achieve_goal (offline)  Sunday, April 29 2012 @ 06:51 AM CDT (Read 1456 times)  
achieve_goal

mark s current age is 1/4 of Ronald's. in 24 years' time, Ronaldd's age will
be 14 years less than twice Mark's age. what is Ronald's age now?


Q2. Janis bought some ice-cream sticks. When Lilin bought 3 times as many ice-
crem sticks as Janis, she had 55 ice-cream sticks more than
1/2 of what Janis had bought. How many ice-cream sticks did
Janis buy?


Q3. Hakim and Suresh had some money in the ratio of 13:8.
When they each received $133,Hakim will have 4 times as much money as Suresh. How much did Hakim had at first?

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By: echeewh (offline)  Monday, April 30 2012 @ 02:48 AM CDT  
echeewh

hey there,

Following pls find the worked solutions: ( *** - used to buffer up the whitespace )

Q1.

Age questions of this kind, one can usually apply the Constant / Unchanged Difference concept, i.e. Age Diff (now) is the same as Age Diff (past or future)

<Now>
R |--|--|--|--|
M |--|

Age Diff (now) = 3u

<24years later>
And applying the Age Diff concept, we have ... ( 3u - indicates the age difference betw R and M in 24 years' time )

*************<-- 24---->
R |--|--|--|--|------------|<-14->
M |--|------------|--|-------------|
******<-- 24---->**<-- 24---->
*****************<-3u->
***<----1p------><----1p------>

Using the Gap & Diff technique, we have ..
3u - 1u ---> 24 - 14 = 10
2u ---> 10
1u ---> 5

Hence, R's age now is = 4u ---> 4 x 5 = 20 years old

=================================================

Q2.

<Before>
J |----|
L |----|----|----|

<After>
After L bought 3x of what J had at first, L had 55 more than 1/2 of what J had.
Split the 1 part of J into 2 units to make the 1/2 of what J had. Likewise, split the 3 parts of what L bought into 2 units per part, giving 6 units (u) in all.

J |--|--|
L |--|--|--|--|--|--|
*****<----55--->

Hence, 5u ---> 55
1u ---> 11
J bought 2u ---> 2 x 11 = 22

=================================================

Q3.
( My Remarks : I think there is some typo in the question - instead of each of them receiving $133 each, it should be giving away $133 each ).


Apply the Constant / Unchanged Difference concept - Difference Before is same as After

<Before>
H : S Diff
13 : 8 5

<After>
4 : 1 3

Hence, we need to multiply <Before> ratio by 3x; <After> ratio by 5x.

<Before>

H : S Diff
39 : 24 15

<After>
20 : 5 15

Notice that there is now a decrease of 19 units from each of H and S.
Now we have ...

19u --> 133
1u --> 7

H (at first) = 39u --> 39 x 7
= $273

=====================================================

Trust the above solutions help.

Any clarification , pls do not hesitate to ask.

Cheers,
Edward

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By: achieve_goal (offline)  Monday, April 30 2012 @ 07:58 AM CDT  
achieve_goal

Quote by: echeewh

hey there,

Following pls find the worked solutions: ( *** - used to buffer up the whitespace )

Q1.

Age questions of this kind, one can usually apply the Constant / Unchanged Difference concept, i.e. Age Diff (now) is the same as Age Diff (past or future)

<Now>
R |--|--|--|--|
M |--|

Age Diff (now) = 3u

<24years later>
And applying the Age Diff concept, we have ... ( 3u - indicates the age difference betw R and M in 24 years' time )

*************<-- 24---->
R |--|--|--|--|------------|<-14->
M |--|------------|--|-------------|
******<-- 24---->**<-- 24---->
*****************<-3u->
***<----1p------><----1p------>

Using the Gap & Diff technique, we have ..
3u - 1u ---> 24 - 14 = 10
2u ---> 10
1u ---> 5

Hence, R's age now is = 4u ---> 4 x 5 = 20 years old

=================================================

Q2.

<Before>
J |----|
L |----|----|----|

<After>
After L bought 3x of what J had at first, L had 55 more than 1/2 of what J had.
Split the 1 part of J into 2 units to make the 1/2 of what J had. Likewise, split the 3 parts of what L bought into 2 units per part, giving 6 units (u) in all.

J |--|--|
L |--|--|--|--|--|--|
*****<----55--->

Hence, 5u ---> 55
1u ---> 11
J bought 2u ---> 2 x 11 = 22

=================================================

Q3.
( My Remarks : I think there is some typo in the question - instead of each of them receiving $133 each, it should be giving away $133 each ).


Apply the Constant / Unchanged Difference concept - Difference Before is same as After

<Before>
H : S Diff
13 : 8 5

<After>
4 : 1 3

Hence, we need to multiply <Before> ratio by 3x; <After> ratio by 5x.

<Before>

H : S Diff
39 : 24 15

<After>
20 : 5 15

Notice that there is now a decrease of 19 units from each of H and S.
Now we have ...

19u --> 133
1u --> 7

H (at first) = 39u --> 39 x 7
= $273

=====================================================

Trust the above solutions help.

Any clarification , pls do not hesitate to ask.

Cheers,
Edward




Thank u for ur help. just 1 more q please. The difference between 1/6 of a number
and 2 times the number is 77. What is the number?
please help me. thank u.

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By: MathIzzzFun (offline)  Monday, April 30 2012 @ 09:36 AM CDT  
MathIzzzFun

The difference between 1/6 of a number
and 2 times the number is 77. What is the number?


number --> 6 units
1/6 --> 1 unit
2 times --> 12 units
difference --> 11 units
11 units --> 77, 1 unit --> 7

number --> 42

cheers.

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By: achieve_goal (offline)  Tuesday, May 01 2012 @ 02:49 AM CDT  
achieve_goal

Quote by: MathIzzzFun

The difference between 1/6 of a number
and 2 times the number is 77. What is the number?


number --> 6 units
1/6 --> 1 unit
2 times --> 12 units
difference --> 11 units
11 units --> 77, 1 unit --> 7

number --> 42

cheers.

[/
p]



hi,
thank u.

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