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 Rosyth school SA1 2011 math
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By: raghulkiru (offline)  Thursday, May 03 2012 @ 07:24 AM CDT (Read 1692 times)  
raghulkiru

four children min, nathan,tom and caleb each have some savings. the amount of money Nathan has is 1/3 of the total amount of money,Tom,Min and Caleb have.The amount of money Tom has is 1/4 of the total amount of money Nathan,Min and Caleb have.The amount of money Min has is 1/5 of the total amount of money Nathan,Tom and Caleb have.If caleb saves $1035,how much do the four children have altogether?

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By: echeewh (offline)  Thursday, May 03 2012 @ 06:42 PM CDT  
echeewh

Hi ,

Following pls find the worked solution:

N = 1u; T + M + C = 3u; Total = 4u --- (1)
T = 1u; N + M + C = 4u; Total = 5u --- (2)
M = 1u; N + T + C = 5u; Total = 6u --- (3)

Applying Unchanged Total concept ( total savings for M, N, T, C is the same for all 3 comparison statements above ), we need to find a common multiple for 4,5,6, which is 60.

Hence, total for each of the above comparisons = 60u.

So we have ...
(1) x 15: N = 15u; T + M + C = 45u; Total = 60u
(2) x 12: T = 12u; N + M + C = 48u; Total = 60u
(3) x 10: M = 10u; N + T + C = 50u; Total = 60u

C = 60u - N - T - M = 60u - 15u - 12u - 10u
= 23u

Given that C saves $1035, we have ...
23u --> 1035
1u --> 1035 / 23 = 45

Total savings of all 4 children = 60u --> 60 x 45 = $ 2700

================================================

Trust the above helps.

Cheers,
Edward

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