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 By: mumof2boys (offline)  Saturday, May 05 2012 @ 02:09 AM CDT (Read 1444 times)
mumof2boys

This problem is similar to the last one about Adam and Tom.
Mr Zaini has a carton with red and green apples. If he adds 10 red apples, 0.6 of the total will be green apples. If he adds in 30 green apples, 3/4 of the total apples will be green. How many apples are there in the carton? Is there a simpler way to answer it than U and P used in the previous solution?
Thanks.

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Registered: 08/22/09
Posts: 6

 By: geniuskids (offline)  Saturday, May 05 2012 @ 08:16 AM CDT
geniuskids

Can I know which section and the question no?tx

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Registered: 11/12/11
Posts: 169

 By: mumof2boys (offline)  Sunday, May 06 2012 @ 04:51 AM CDT
mumof2boys

it's Paper 2, no. 18. I could solve it using parts and units. just want to know if there is any other way to do it?

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Registered: 08/22/09
Posts: 6

 By: echeewh (offline)  Monday, May 07 2012 @ 10:17 PM CDT
echeewh

Hey mumof2boys,

Im not sure if your method using parts n units is the same as my solution by model method. In Maths sometimes there can be more than 1 approach to the question itself. Since you are seeking another method besides parts n units ( which i believe is using model concept ), we can use the Simultaneous concept here. This is how it works.

To arrive to this <Before> model for the R apples, we need to subtract 10 from the 4p.

<Before>
G: 6p
R: 4p - 10

<Process>

<After>
G: 3u
R: 1u

6p + 30 --> 3u --- (1)
4p - 10 --> 1u --- (2)

Since question is asking for number of apples in carton at start, we shall eliminate (u). So ...

(2) x 3: 12p - 30 --> 3u --- (3)

Compare (3) with (1), subtracting (1) from (3) will eliminate (u).

(3) - (1): 12p - 6p - 30 - 30 --> 0
6p --> 60
1p --> 10

Hence, number of apples in carton (at start) = 10p - 10 --> ( 10 x 10 ) - 10 = 90

==================================

Trust the above helps.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

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