
By: geniuskids (offline) Saturday, May 05 2012 @ 10:57 PM CDT (Read 1100 times)



geniuskids 
Hi, would appreciate anyone help to give solution on this question!
Btw, its given from school and not from any past year test paper !
(Q) Vernice had $1196 more than Ethan. If vernice were to give 1/7 of her money to Ethan, she would have 4 times as much money as Ethan. How much money did Ethan have?
So much thanks!

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Registered: 11/12/11 Posts: 169





By: tancrowhurst (offline) Sunday, May 06 2012 @ 01:25 AM CDT



tancrowhurst 
Draw a After model. I don't know how to do it here.
After,
V : E
6 parts : 1 parts + ?
x2 x2
V has 4 times as much as E
12 units= 4 (?) = 4x3 units
E has 3 units after given 1/7 (2 units) of what V had.
E has only 1 unit at first.
Before,
14u = 1u + 1196
13u = 1196
1u = 92
Ethan had $92.

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Registered: 05/05/12 Posts: 8





By: echeewh (offline) Sunday, May 06 2012 @ 01:28 AM CDT



echeewh 
Hi there,
Following pls find worked solution..
<After>
V: 4p
E: 1p
The 4p of V is the 6/7 of her money left ( or 6 parts of her money left ). Hence need to split the 4p into smaller equal units (u) to represent this 6/7 of V's money. Applying Common Multiple method, the LCM of 4 and 6 gives 12.
We now have ...
<After>
V: 4p x 3 = 12u
E: 1p x 3 = 3u
<Process>
So this 12u of V's money left > 6/7 money left. To get to V's original amount, we have ...
V: 12 x 7 / 6 = 14u ( an increase of 2u  this 2u is the 1/7 equivalent given to E )
So E = 3u  2u = 1u
<Before>
V: 14u
E: 1u
Given that V  E = $1196, we have ...
13u > 1196
1u > 1196 / 13 = 92
So E = 1u > $92.
====================
Trust this helps.
Cheers,
Edward

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Registered: 04/21/11 Posts: 623





By: geniuskids (offline) Sunday, May 06 2012 @ 01:44 AM CDT



geniuskids 
Thanks guys, you were both great! Can help solve the other questions (past year test papers) posted by "geniuskids". Many thanks!
Hi Edward, I understand your explanation except the using of LCM 4 & 6 which I am not sure how to fully explain to my boy. Pls clarify

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Registered: 11/12/11 Posts: 169





By: echeewh (offline) Sunday, May 06 2012 @ 03:43 AM CDT



echeewh 
LCM = lowest common multiple. Im sure ur kid is able to list out the multiple for 4, 6 and establish the lowest one. Of cos, the easier way out for most of us is to multiply 4 and 6 to give u the common multiple (which may not be the lowest ). You will still be able to get the same answer with this.
Cheers,
Edward

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Registered: 04/21/11 Posts: 623





By: geniuskids (offline) Sunday, May 06 2012 @ 04:09 AM CDT



geniuskids 
tHANKS eDWARD... my boy finally understands

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Registered: 11/12/11 Posts: 169



