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 By: geniuskids (offline)  Saturday, May 05 2012 @ 10:57 PM CDT (Read 1264 times)
geniuskids

Hi, would appreciate anyone help to give solution on this question!
Btw, its given from school and not from any past year test paper !

(Q) Vernice had \$1196 more than Ethan. If vernice were to give 1/7 of her money to Ethan, she would have 4 times as much money as Ethan. How much money did Ethan have?

So much thanks!

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Registered: 11/12/11
Posts: 169

 By: tancrowhurst (offline)  Sunday, May 06 2012 @ 01:25 AM CDT
tancrowhurst

Draw a After model. I don't know how to do it here.

After,
V : E
6 parts : 1 parts + ?
x2 x2
V has 4 times as much as E
12 units= 4 (?) = 4x3 units
E has 3 units after given 1/7 (2 units) of what V had.
E has only 1 unit at first.

Before,
14u = 1u + 1196
13u = 1196
1u = 92

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Registered: 05/05/12
Posts: 8

 By: echeewh (offline)  Sunday, May 06 2012 @ 01:28 AM CDT
echeewh

Hi there,

Following pls find worked solution..

<After>
V: 4p
E: 1p

The 4p of V is the 6/7 of her money left ( or 6 parts of her money left ). Hence need to split the 4p into smaller equal units (u) to represent this 6/7 of V's money. Applying Common Multiple method, the LCM of 4 and 6 gives 12.

We now have ...

<After>
V: 4p x 3 = 12u
E: 1p x 3 = 3u

<Process>
So this 12u of V's money left --> 6/7 money left. To get to V's original amount, we have ...

V: 12 x 7 / 6 = 14u ( an increase of 2u - this 2u is the 1/7 equivalent given to E )
So E = 3u - 2u = 1u

<Before>
V: 14u
E: 1u

Given that V - E = \$1196, we have ...

13u --> 1196
1u --> 1196 / 13 = 92

So E = 1u --> \$92.

====================

Trust this helps.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

 By: geniuskids (offline)  Sunday, May 06 2012 @ 01:44 AM CDT
geniuskids

Thanks guys, you were both great! Can help solve the other questions (past year test papers) posted by "geniuskids". Many thanks!

Hi Edward, I understand your explanation except the using of LCM 4 & 6 which I am not sure how to fully explain to my boy. Pls clarify

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Registered: 11/12/11
Posts: 169

 By: echeewh (offline)  Sunday, May 06 2012 @ 03:43 AM CDT
echeewh

LCM = lowest common multiple. Im sure ur kid is able to list out the multiple for 4, 6 and establish the lowest one. Of cos, the easier way out for most of us is to multiply 4 and 6 to give u the common multiple (which may not be the lowest ). You will still be able to get the same answer with this.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

 By: geniuskids (offline)  Sunday, May 06 2012 @ 04:09 AM CDT
geniuskids

tHANKS eDWARD... my boy finally understands

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Registered: 11/12/11
Posts: 169

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