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 By: Strawberry (offline)  Sunday, May 06 2012 @ 07:06 AM CDT (Read 1370 times)
Strawberry

1. Jerry bought four times as many pencils as notebooks and spent a total of \$21.60. He spent \$2.40 more on the notebooks than the pencils. Given that a notebook costs \$3.20 more than a pencil, find the cost of a pencil.

2. Ms Lee baked 24 more chocolate muffins than banana muffins. After she gave away1/6 of the chocolate muffins and 3/8 of the banana muffins, she left with 35 more chocolate muffins than banana muffins. How many chocolate muffins did she bake at first?

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Registered: 01/31/09
Posts: 83

 By: echeewh (offline)  Sunday, May 06 2012 @ 10:18 PM CDT
echeewh

Hey strawberry,

Following pls find worked solution:

Q1.

Use Comparison model to calculate cost of notebooks (N) and pencils (P) as follows:

21.60 - 2.40 = 19.20
19.20 / 2 = 9.60 ( Cost of P )
Cost of N = 9.60 + 2.40 = 12.00

Given that 4u of P and 1u of N were bought, we can now calculate the cost of 1u of P.

1u of P = 9.60 / 4 = 2.40
1u of N = 12.00

Difference in cost ( 1u N - 1u P )
= 12.00 - 2.40 = 9.60

Given that N - P = 3.20,

1u N = 9.60 / 3.20 = 3 ( 1u N = 1u P )

Number of P = 4u = 4 x 3 = 12
Cost of 1P = 9.60 / 12 = \$0.80 ( 80 cents )

=======================================

Q2

Using Simultaneous Eqn method ( aka Compare & Replace / Elimination ), we have ...

<Before>
C - B = 24 --- (1)
<After>
5/6 C - 5/8 B = 35 --- (2)

Since question is only asking for C at first, eliminate B as follows:

(1) x 5/8: 5/8 C - 5/8 B = 15 --- (3)

Compare (2) and (3), we subtract (3) from (2) to eliminate B as follows:

(2) - (3): 5/6 C - 5/8 C = 20
5/24 C = 20
C = 20 x 24 / 5 = 96

=================================

Trust the above helps.

Do clarify , if any.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

 By: Strawberry (offline)  Sunday, May 06 2012 @ 11:15 PM CDT
Strawberry

thank you... it is very clear..

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Registered: 01/31/09
Posts: 83

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