
By: fanny6573 (offline) Monday, May 14 2012 @ 08:46 PM CDT (Read 1620 times)



fanny6573 
Please help to solve this!
Varsha had some 20cents & 50cents coins. 7/8 of the coins were 20cent coins & the rest were 50cents.
After Varsha had spent $72.50 worth of 50cent coins and 5/7 of the 20cent coins, she had 2/7 of the coins left.
Find the total amount of money Varsha left.
The answer is $110.20
Thanks.

Junior
Registered: 07/19/10 Posts: 28





By: kkkhai (offline) Tuesday, May 15 2012 @ 03:20 AM CDT



kkkhai 
Hello there (: It's just your luck that I love to challenge myself with these types of word problems. do take a look at the .jpeg attachment and I hope it helps.
Usually, I would spend time to verbally explain but since I can't do that here, I've jotted notes in BROWN ink for you.
http://dl.dropbox.com/u/29603635/RGS%20 ... %20Q17.jpg

Newbie
Registered: 04/30/10 Posts: 1





By: echeewh (offline) Tuesday, May 15 2012 @ 03:48 AM CDT



echeewh 
Hey there,
Following pls find the worked solution:
<Before>
20cts: 7p
50cts: 1p
Total: 8p of coins.
<Process>
$72.50 (of 50cts) and 5/7 of 20cts spent.
72.50 / 0.50 = 145 (50cts) spent.
Given that 2/7 of the total coins were left and initial total coins is 8p, we split 1p of these into 7 equal units (u); hence, giving (8 x 7) = 56u (initial total.
So we have ...
<Before>
20cts: 49u
50cts: 7u
<Process>
2/7 of 20cts coins left = (2/7) x 49 = 14u.
2/7 of total coins left = (2/7) x 56 = 16u.
Therefore, 50cts coins left = 16u  14u = 2u
<After>
20cts: 14u
50cts: 2u
Knowing that 145 (50cts) coins were spent, we have ...
5u > 145
1u > 29
20cts: 14u > 14 x 29 = 406
Amt (20cts): 406 x 0.20 = $81.20
50cts: 2u > 2 x 29 = 58
Amt (50cts): 58 x 0.50 = $29
Total amt left = $81.20 + $29 = $110.20
=============================================
Trust the above helps.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: fanny6573 (offline) Thursday, May 17 2012 @ 01:46 AM CDT



fanny6573 
Thanks for the useful solution.

Junior
Registered: 07/19/10 Posts: 28



