Sign Up!
Login
Welcome to Test-paper.info
Friday, November 24 2017 @ 10:44 AM CST
 Forum Index >  Test Paper Related >  Primary 6 Matters
 RGS -SA1 2011, Q17
   |  Printable Version
By: fanny6573 (offline)  Monday, May 14 2012 @ 08:46 PM CDT (Read 1620 times)  
fanny6573

Please help to solve this!

Varsha had some 20-cents & 50-cents coins. 7/8 of the coins were 20-cent coins & the rest were 50-cents.
After Varsha had spent $72.50 worth of 50-cent coins and 5/7 of the 20-cent coins, she had 2/7 of the coins left.
Find the total amount of money Varsha left.

The answer is $110.20

Thanks.

Forum Junior
Junior

Registered: 07/19/10
Posts: 28

Profile Email    
   
By: kkkhai (offline)  Tuesday, May 15 2012 @ 03:20 AM CDT  
kkkhai

Hello there (: It's just your luck that I love to challenge myself with these types of word problems. do take a look at the .jpeg attachment and I hope it helps.

Usually, I would spend time to verbally explain but since I can't do that here, I've jotted notes in BROWN ink for you.

http://dl.dropbox.com/u/29603635/RGS%20 ... %20Q17.jpg

Forum Newbie
Newbie


Registered: 04/30/10
Posts: 1

Profile Email    
   
By: echeewh (offline)  Tuesday, May 15 2012 @ 03:48 AM CDT  
echeewh

Hey there,

Following pls find the worked solution:

<Before>
20cts: 7p
50cts: 1p

Total: 8p of coins.

<Process>
$72.50 (of 50cts) and 5/7 of 20cts spent.
72.50 / 0.50 = 145 (50cts) spent.
Given that 2/7 of the total coins were left and initial total coins is 8p, we split 1p of these into 7 equal units (u); hence, giving (8 x 7) = 56u (initial total.

So we have ...

<Before>
20cts: 49u
50cts: 7u

<Process>
2/7 of 20cts coins left = (2/7) x 49 = 14u.
2/7 of total coins left = (2/7) x 56 = 16u.
Therefore, 50cts coins left = 16u - 14u = 2u

<After>
20cts: 14u
50cts: 2u

Knowing that 145 (50cts) coins were spent, we have ...
5u --> 145
1u --> 29

20cts: 14u --> 14 x 29 = 406
Amt (20cts): 406 x 0.20 = $81.20

50cts: 2u --> 2 x 29 = 58
Amt (50cts): 58 x 0.50 = $29

Total amt left = $81.20 + $29 = $110.20

=============================================

Trust the above helps.

Cheers,
Edward

Forum Active Member
Active Member

Registered: 04/21/11
Posts: 627

Profile Email    
   
By: fanny6573 (offline)  Thursday, May 17 2012 @ 01:46 AM CDT  
fanny6573

Thanks for the useful solution.

Forum Junior
Junior

Registered: 07/19/10
Posts: 28

Profile Email    
   


 All times are CST. The time is now 10:44 am.
Normal Topic Normal Topic
Locked Topic Locked Topic
Sticky Topic Sticky Topic
New Post New Post
Sticky Topic w/ New Post Sticky Topic w/ New Post
Locked Topic w/ New Post Locked Topic w/ New Post
View Anonymous Posts 
Able to Post 
HTML Allowed 
Censored Content