Welcome to Test-paper.info
Saturday, February 24 2018 @ 07:54 PM CST
 Select a Forum » General Chat » Primary 1 Matters » Primary 2 Matters » Primary 3 Matters » Primary 4 Matters » Primary 5 Matters » Primary 6 Matters » Question, Feedback and Comments » Education Classified
 Forum Index >  Test Paper Related >  Primary 6 Matters Henry Park 2011 Math SA1 Paper 2 Q8
 | Printable Version
 By: kyChang (offline)  Friday, May 25 2012 @ 12:40 AM CDT (Read 1213 times)
kyChang

Anyone can help to show the working

Candy was given some money to buy some stationery. She spent all her money to buy pens that cost \$0.80 each.
If she had spent her money to buy highlighters that cost \$1.30 each, the number of highlighters bought would be 5 fewer that the pens.
How many pens did she buy?

Junior

Registered: 10/10/10
Posts: 21

 By: echeewh (offline)  Saturday, May 26 2012 @ 10:24 PM CDT
echeewh

Hey there,

Following pls find the worked solution..

Given same amt spent on both Pens (P) and Highlighters (H), the number of P bought was 5 more than H.

Implies that the cost of these 5 P was used to buy a number of H (with same total amt of money).

This is also the 'extra' money used to pay for that number of H bought (and same number of P). This 'extra' money is a result of the diff in price between 1 H and 1 P

Cost of these 5 P = 5 x 0.80 = \$4

Given the price diff between 1 H and 1 P is ( 1.30 - 0.80 = 0.50 ), we have ...

Number of H bought = 4.00 รท 0.50 = 8

Hence, number of P bought = 8 + 5 = 13

========================================

Trust the above helps to clarify.

Let me know again if necessary

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: kyChang (offline)  Tuesday, June 05 2012 @ 03:19 AM CDT
kyChang

Forgot to Thank u

Junior

Registered: 10/10/10
Posts: 21

 All times are CST. The time is now 07:54 pm.
 Normal Topic Locked Topic Sticky Topic
 New Post Sticky Topic w/ New Post Locked Topic w/ New Post
 View Anonymous Posts Able to Post HTML Allowed Censored Content