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 By: kyChang (offline)  Friday, May 25 2012 @ 12:55 AM CDT (Read 864 times)
kyChang

On a weekend, the ratio of the mass of cabs sold to the mass of prawns sold was 3:2.
The ratio of the mass of lobsters sold to the mass of crabs sold was 1:5. The total amount
of money collected from the sale of 3 seafood items for the weekend was \$9870.
Find the difference in mass between the sale of prawns and lobsters during the weekend.

Price of seafood item (per kilogram)
Cabs = \$18
Prawns = \$12.50
Lobsters = \$25

Junior

Registered: 10/10/10
Posts: 21

 By: echeewh (offline)  Saturday, May 26 2012 @ 08:52 PM CDT
echeewh

Hey there,

Following pls find the worked solution,

C : P : L
3 : 2 --- (1)
5 1 --- (2)

Using Repeeated/Common Identity with C being common in these 2 ratios, C must have the same units (u) as the mass of C sold is the same.

Hence, common multiple of 5 and 3 is 15. We now have

(1)x5 and (2)x3.

C : P : L
15 : 10
15 3

Given that \$9870 was collected from the sale of these 3 items, we have ...

<using Number x Value method>

(15u x 18) + (10u x 12.50) + (3u x 25) --> 9870
270u + 125u + 75u --> 9870
470u --> 9870
1u --> 21

Sale of P = 125u --> 125 x 21 = 2625
Sale of L = 75u --> 75 x 21 = 1575

Mass of P = 2625 ÷ 12.50 = 210 kg
Mass of L = 1575 ÷ 25 = 63 kg

Difference in mass ( P - L ) = 210 - 63 = 147 kg

==============================================

Trust the above helps.

Do not hesitate to clarify if necessary.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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