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Wednesday, December 13 2017 @ 04:47 PM CST
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 P 5 Maths problems
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By: JessicaTan (offline)  Monday, May 28 2012 @ 04:02 AM CDT (Read 1085 times)  
JessicaTan

Anybody can me solve these problem?

1) Moses had a total of 408 blue and green counters at first. He lost 3/5 of his blue counters and bought another 32 green counters. Then the number of green counters he had was 1/4 of the number of the blue counters left. How many more blue counters than green counters did Moses have at first? (ans : 392) please show me the details working





2) There were 225 more packets of sugar in Store A than in Store B. After 33 packets of sugar were transferred from Store B to Store A, there were 4 times as many packets of sugar in Store A as in Store B. How many packets of sugar were there in Store A at first? (ans : 355) (Please show me the detail working)



Rdgs & Thanks
Jessica

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Registered: 10/17/09
Posts: 82

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By: echeewh (offline)  Monday, May 28 2012 @ 07:03 AM CDT  
echeewh

Hi Jessica,

Following pls find the worked solutions:

Q1.

<after>
G : B
1 : 4

Working Backwards, we have ...

<Before>
G:
1u - 32

B:
2/5 left = 4u
5/5 (at first) = 4 ÷ (2/5)
= 4 x (5/2) = 10u

Given that there were 408 B and G at first, we have...

1u - 32 + 10u --> 408
11u --> 408 + 32 = 440
1u --> 40

At first, B = 10u --> 10 x 40 = 400
At first, G = 1u - 32 --> 40 - 32 = 8

Hence, B - G = 400 - 8 = 392

=================================================

Q2.

<After>
A : B
4 : 1

<Process>
33 pkts transferred frm B to A.

Working Backwards, we have ...

A: 4u - 33
B: 1u + 33

At first, A - B = 225

Hence, we have ....

4u - 33 - 1u - 33 --> 225
3u --> 225 + 33 + 33 = 291
1u --> 291 ÷ 3 = 97

At first, A = 4u - 33 --> (4 x 97) - 33 = 355

=============================================

Trust the above helps.

Cheers,
Edward

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Posts: 627

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