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 By: 2000123 (offline)  Wednesday, May 30 2012 @ 08:36 PM CDT (Read 1574 times)
2000123

Q11.

Q12.
Leon bought some guppies and terrapins for a total of \$96. He bought 3 times as many guppies as terrapins. He paid \$30 more for the terrapins than for the guppies. Each terrapin cost \$10.40 more than each guppy.
(a)How many terrapins did he buy?

(b) What was the cost of each guppy?

Junior

Registered: 03/07/12
Posts: 21

 By: echeewh (offline)  Thursday, May 31 2012 @ 12:32 PM CDT
echeewh

Hey there,

Q11

(Note: *** - used to buffer whitespace to create alignment; imagine these are all spaces )

Apply <Branching method>

*******|--> 3/4 + 3/4 b (S)
Total -|******************|--> 3/4 + 3/4 b (Y)
*******|--> 1/4 - 3/4 b - |
**************************|--> 1/4 - 3/4 b = 1 b (A)

In other words,

From Total, S = 3/4 + 3/4 b
Remainder (R) = 1/4 - 3/4 b
From R, Y = 3/4 + 3/4 b
Remainder (R1) = 1/4 - 3/4 b

Given that A received the last bead in the bag, then ...
R1 = 1/4 - 3/4 b = 1 b

So, 1/4 = 1 3/4 b

Working Backwards, we have ...
R = 4/4 = (7/4) x 4 = 7 b

So we have ...
R = 1/4 - 3/4 b = 7 b
1/4 = 7 3/4 b

S = 3/4 + 3/4 b
= 3 x (31/4 b) + 3/4 b = 93/4 b + 3/4 b
= 96/4 b = 24 b

=============================================================

Q12

Cost/Price model:

T |---------------------| } T + G
G |----------|<-------> } = 96
30

G:
96 - 30 = 66
66 ÷ 2 = 33

T:
33 + 30 = 63

Qty / Number ratio:

G : T
3 : 1

So, 3u of G cost \$33; 1u of T cost \$63.
Hence, 1u of G cost \$11.

Comparing the cost of 1u of T and G, the difference is ...

T - G = 63 - 11 = 52

(a)

Given that cost of 1 T is \$10.40 more than 1 G,
number of T = 52 ÷ 10.40 = 5

(b)

5G = 11
1G = 11 ÷ 5 = \$2.20

==========================================================

Trust the above helps.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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