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 By: sundarshoba (offline)  Tuesday, July 03 2012 @ 09:25 AM CDT (Read 1026 times)
sundarshoba

Please assist to work out the steps for the attached questions. Thks

Chatty

Registered: 12/31/06
Posts: 53

 By: GIM (offline)  Wednesday, July 04 2012 @ 09:06 AM CDT
GIM

Q5 During a basketball match, the teacher promised a team of 8 pupils an equal playing time during the 40 minuts match. Given that only 5 players can play at any one time.What is the average playing time for each player?

Solution:
Total players : 8
Total playing time : 40 minutes
Each game : 5 players

If every player has equal playing time, the possible arrangements have to be as follows :
1st set players : 12345
2nd set players : 67812
3rd set players : 34567
4th set players : 81234
5th set players : 56781
6th set players : 23456
7th set players : 78123
8th set players : 45678
9th set players : 12345 (repeat 1st set players)

1 complete pattern is 8 sets
From the above arrangements, each player appeared 5 times from 1st to 8th set.

Each set is allowed playing time : 40minutes / 8 = 5 minutes
Each player gets to play : 5 x 5 minutes = 25 minutes.

Regular Member

Registered: 11/07/10
Posts: 70

 By: echeewh (offline)  Wednesday, July 04 2012 @ 04:32 PM CDT
echeewh

Hey Sundar,

An efficient but similar solution to this would be :

Average playing time per pupil = Total playing time / Total number of pupils

Total playing time = 5 x 40 = 200
Total number of pupils = 8

Hence, Average playing time per pupil = 200 / 8 = 25 mins

============================

Trust this helps.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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