Sign Up!
Login
Welcome to Test-paper.info
Wednesday, August 23 2017 @ 01:25 AM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 ACS 2010 PRE
   |  Printable Version
By: sundarshoba (offline)  Friday, July 06 2012 @ 12:20 AM CDT (Read 727 times)  
sundarshoba

Please help to check and solve the attached questions, thank you very much.

Forum Chatty
Chatty

Registered: 12/31/06
Posts: 53

Profile Email    
   
By: echeewh (offline)  Friday, July 06 2012 @ 08:08 AM CDT  
echeewh

Hey Sundar,

Following pls find my worked solution:

Q14. (ACS Prelim 2010 Paper 2)

Diameter of Circle = 30 cm; Radius of circle = 15 cm

Given that A, B, C are centres of respective circles, AC = AB = CB = diameter = 30 cm

Therefore, triangle ABC is an equilateral triangle in which all 3 interior angles = 60° each.

Area of shaded circle (centre C)
= (300/360) x pi x 15 x 15
= (5/6) x pi x 225 = (1125 x pi) / 6

Total Shaded Area = 3 x [(1125 x pi) / 6]
= (1125 x pi) / 2 = 1767.15 cm2

================================

As for the other question, it was already posted by another person and I 'm still looking into the solution.

Trust this helps.

Any clarification , pls do let me know again.

Cheers,
Edward

Forum Active Member
Active Member

Registered: 04/21/11
Posts: 625

Profile Email    
   


 All times are CDT. The time is now 01:25 am.
Normal Topic Normal Topic
Locked Topic Locked Topic
Sticky Topic Sticky Topic
New Post New Post
Sticky Topic w/ New Post Sticky Topic w/ New Post
Locked Topic w/ New Post Locked Topic w/ New Post
View Anonymous Posts 
Able to Post 
HTML Allowed 
Censored Content