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 Forum Index >  Test Paper Related >  Primary 6 Matters
 Nanyang PRE 2010 Paper 2
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By: sundarshoba (offline)  Saturday, July 07 2012 @ 04:44 PM CDT (Read 1155 times)  
sundarshoba

Thank you very much and here comes the next challenges, please

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By: echeewh (offline)  Saturday, July 07 2012 @ 08:36 PM CDT  
echeewh

Hey Sundar,

Following pls find my worked solution for Q7.

Promo A: 4 for $3.60
Promo B: 7 for $6.00
Hence, Promo B per doughnut works out cheaper than Promo A.

320 รท 7 = 45 groups of Promo B
45 x 7 = 315 doughnuts

Remaining 5 doughnuts:
1 group of Promo A = 4
1 doughnut at $1.20

Total amt = (45 x 6) + 3.60 + 1.20
= $274.80

========================================

Trust this helps.

Cheers,
Edward

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By: echeewh (offline)  Sunday, July 08 2012 @ 05:40 PM CDT  
echeewh

<Jul 9 - Added>

Refer to attached worked solution for Q11.
All working shown are for Diagram B.
(correction: replace "Tank B" with "Diagram B" )

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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