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 By: sundarshoba (offline)  Saturday, July 07 2012 @ 04:44 PM CDT (Read 1170 times)
sundarshoba

Thank you very much and here comes the next challenges, please

Chatty

Registered: 12/31/06
Posts: 53

 By: echeewh (offline)  Saturday, July 07 2012 @ 08:36 PM CDT
echeewh

Hey Sundar,

Following pls find my worked solution for Q7.

Promo A: 4 for \$3.60
Promo B: 7 for \$6.00
Hence, Promo B per doughnut works out cheaper than Promo A.

320 รท 7 = 45 groups of Promo B
45 x 7 = 315 doughnuts

Remaining 5 doughnuts:
1 group of Promo A = 4
1 doughnut at \$1.20

Total amt = (45 x 6) + 3.60 + 1.20
= \$274.80

========================================

Trust this helps.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: echeewh (offline)  Sunday, July 08 2012 @ 05:40 PM CDT
echeewh

Refer to attached worked solution for Q11.
All working shown are for Diagram B.
(correction: replace "Tank B" with "Diagram B" )

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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