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 By: sundarshoba (offline)  Sunday, July 08 2012 @ 09:27 AM CDT (Read 1046 times)
sundarshoba

Chatty

Registered: 12/31/06
Posts: 53

 By: MathIzzzFun (offline)  Sunday, July 08 2012 @ 06:12 PM CDT
MathIzzzFun

Quote by: sundarshoba

hi

solution for Q17.

cheers.

Chatty

Registered: 04/02/10
Posts: 36

 By: echeewh (offline)  Monday, July 09 2012 @ 04:17 PM CDT
echeewh

Hey there,

Pls find worked solution for Q16 as follows:

Vol of water in A (at first) = 15 x 20 x 21 cm3
= 6300 m3

(1/4) of these were released to B
= (1/4) x 6300 = 1575 m3

(a)
Vol of water in B (at height of 7 m)
= 15 x 10 x 7 = 1050 m3
Hence, vol of water in C = 1575 - 1050 = 525 m3

Given that height of water level in C is same as in B (7 m), we have ...

Length of C = [Vol / (15 x 7)] = [525 / 105]
= 5 m

(b) 525 m3

===============================

Trust the above helps.

Do let me know again if there's any clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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