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Monday, November 20 2017 @ 05:59 AM CST
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 P6 Volume Question
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By: KCTAN (offline)  Friday, July 20 2012 @ 10:29 AM CDT (Read 1195 times)  
KCTAN

Hi,

Would greatly appreciate if someone could guide me through this question:

Tank A was completely filled with water.
3/4 of the water from Tank A was poured into Tank B and could only fill 1/3 of it.
If the capacity of Tank B is 5000cm3 more than the capacity of Tank A and the base area
of Tank A was 250cm2, find the height of Tank A.

Thank you.

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By: echeewh (offline)  Saturday, July 21 2012 @ 08:15 PM CDT  
echeewh

Hey KCTan,

Following pls find my worked solution :

(3/4) A = (1/3) B

Applying <Equal Concept>, we have ...

(3/4) A = (3/9) B

Hence, A = 4u ; B = 9u (= capacities of A, B in units)

Given that capacity of Tank B is 5000cm3 more than the capacity of Tank A, we have ...

9u - 4u --> 5000
5u --> 5000
1u --> 1000

So capacity of Tank A = 4u --> 4 x 1000 = 4000 cm3

Given that base area of Tank A was 250 cm2,

Height (A) = Capacity (Vol in A) ÷ Base Area (A)
= 4000 ÷ 250
= 16 cm

===================================

Trust this helps.

Do let me know again if this answer does not match your Answerkey or if you have further clarification. Btw, is this a 3-mark question?

Cheers,
Edward

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By: KCTAN (offline)  Sunday, July 22 2012 @ 08:22 AM CDT  
KCTAN

Hi Edward,

Wow! Thank you so so much for your help on this.
Your explanation is very clear to me.
I understand it now. Smile

I do not know how many marks this question is but
it is one of the many problem sums in the revision paper given by teacher. Rolling Eyes

Thank you and have a good week ahead!

Smile Smile

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