
By: KCTAN (offline) Friday, July 20 2012 @ 10:29 AM CDT (Read 1168 times)



KCTAN 
Hi,
Would greatly appreciate if someone could guide me through this question:
Tank A was completely filled with water.
3/4 of the water from Tank A was poured into Tank B and could only fill 1/3 of it.
If the capacity of Tank B is 5000cm3 more than the capacity of Tank A and the base area
of Tank A was 250cm2, find the height of Tank A.
Thank you.

Newbie
Registered: 11/02/11 Posts: 9





By: echeewh (offline) Saturday, July 21 2012 @ 08:15 PM CDT



echeewh 
Hey KCTan,
Following pls find my worked solution :
(3/4) A = (1/3) B
Applying <Equal Concept>, we have ...
(3/4) A = (3/9) B
Hence, A = 4u ; B = 9u (= capacities of A, B in units)
Given that capacity of Tank B is 5000cm3 more than the capacity of Tank A, we have ...
9u  4u > 5000
5u > 5000
1u > 1000
So capacity of Tank A = 4u > 4 x 1000 = 4000 cm3
Given that base area of Tank A was 250 cm2,
Height (A) = Capacity (Vol in A) ÷ Base Area (A)
= 4000 ÷ 250
= 16 cm
===================================
Trust this helps.
Do let me know again if this answer does not match your Answerkey or if you have further clarification. Btw, is this a 3mark question?
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 623





By: KCTAN (offline) Sunday, July 22 2012 @ 08:22 AM CDT



KCTAN 

Newbie
Registered: 11/02/11 Posts: 9



