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 By: KCTAN (offline)  Wednesday, July 25 2012 @ 07:16 AM CDT (Read 1065 times)
KCTAN

Hi,

Would appreciate some help on the following (5marks) questions:

1. John had 72 more mangoes than oranges.
After selling 3/4 of the mangoes and 3/5 of the oranges, he was left with 15 more oranges than mangoes.
The mangoes were sold at \$2.75 each and the oranges at \$0.55 each.
How much money did he receive altogether?

2. There were some green paper clips and blue paper clips in a box.
If 44 green paper clips were to be removed from the box, the ratio of the number of green paper clips to the
number of blue paper clips would be 4:5.
If 20 blue paper clips were to be removed from the box instead, the ratio of the number of green paper clips to
the number of blue paper clips would be 6:5.
When another 150 blue paper clips were put into the box, what percentage of all the paper clips in the box
would be blue paper clips in the end?

Thank you.

Newbie

Registered: 11/02/11
Posts: 9

 By: jo sarah (offline)  Saturday, July 28 2012 @ 09:48 AM CDT
jo sarah

hi,

1. let there be 20 units of oranges; so, 20 units (u) + 72 mangoes.
He sold 3/4 of mangoes, ie., 15 u + 54 mangoes
and 3/5 oranges, ie., 12 u oranges

He was left with 5 u + 18 mangoes and 8 u oranges.
ie., 8 u - (5 u + 18) = 15
3 u = 33
1 u = 11

(15 x 11 + 54) x \$2.75 + (12 x 11) x \$0.55 = \$674.85

2. [could be easiest solved using simultaneous equations, which some P6 kids do know how to do.
So, i try to show this approach. For other approaches, perhaps others could show how.]

Let there be g green clips and b blue clips.
Then, g - 44 : b = 4 : 5
ie., 5g - 220 = 4b
or, 5g = 4b + 220 ...... (1)
And, g : b - 20 = 6 : 5
ie., 5g = 6b - 120 ...... (2)
(2) - (1): 2b = 340
so that, b = 170
and g = 180

When add 150 blue into box, Percentage of blue in box in the end
= (150 + 170) / (150 + 170 + 180) x 100% = 64%

jo sarah

Regular Member

Registered: 03/20/12
Posts: 111

 By: KCTAN (offline)  Sunday, July 29 2012 @ 01:45 AM CDT
KCTAN

Thank you so much, Jo Sarah!
You have been a great help.

If anyone knows of other methods, please feel free to
share for all to learn as well. Thank you!

Newbie

Registered: 11/02/11
Posts: 9

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