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 By: shirley wee (offline)  Saturday, August 04 2012 @ 03:30 AM CDT (Read 948 times)
shirley wee

Hi! I am confused with the solution to these questions. Can you help me?
These are the questions:

1. Mr. Tan had some sweets for the children who came to his party. If he had given each child 4 sweets, he would need another 10 sweets. If he had given each child 7 sweets, he would need another 130 sweets. How many children were there at the party?

2. A bag contains pink, green and yellow balls. 2/5 of the balls are pink. The number of green balls is 3/5 of the number of yellow balls. There are 24 more yellow balls than green balls. How many balls are there altogether?

Thank you.

Chatty

Registered: 02/28/12
Posts: 68

 By: Hoang Quang Anh (offline)  Saturday, August 04 2012 @ 10:09 PM CDT
Hoang Quang Anh

You should use elimination for question 1

Here's the answer for question number 2:

1- 2/5 = 3/5

3 + 5 = 8

3/5 devde by 8 = 3/40

3/40 X 2 = 3/20

3/20 equal 24

24 divide 3/20 = 160

Ans: 160

Newbie

Registered: 06/05/12
Posts: 11

 By: echeewh (offline)  Monday, August 06 2012 @ 07:10 PM CDT
echeewh

Hi Shirley,

Following pls find my worked solutiion for Q1:

Q1.

Let number of children be u.

<------- 4u ------------>
|----------------|<-10->|
|----------------|<-------130--------->|
<------------- 10u -------------------->
**********************<--- gap -->

Using <Gap & Difference> technique, we have ...

10u - 4u --> 130 - 10
6u --> 120
1u --> 20

Number of Children = 20

====================

Trust this helps.

Do let me know again if this does not match your Answerkey or if there's any clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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