
By: shirley wee (offline) Saturday, August 04 2012 @ 03:30 AM CDT (Read 807 times)



shirley wee 
Hi! I am confused with the solution to these questions. Can you help me?
These are the questions:
1. Mr. Tan had some sweets for the children who came to his party. If he had given each child 4 sweets, he would need another 10 sweets. If he had given each child 7 sweets, he would need another 130 sweets. How many children were there at the party?
2. A bag contains pink, green and yellow balls. 2/5 of the balls are pink. The number of green balls is 3/5 of the number of yellow balls. There are 24 more yellow balls than green balls. How many balls are there altogether?
Thank you.

Chatty
Registered: 02/28/12 Posts: 68





Hoang Quang Anh 
You should use elimination for question 1
Here's the answer for question number 2:
1 2/5 = 3/5
3 + 5 = 8
3/5 devde by 8 = 3/40
3/40 X 2 = 3/20
3/20 equal 24
24 divide 3/20 = 160
Ans: 160

Newbie
Registered: 06/05/12 Posts: 11





By: echeewh (offline) Monday, August 06 2012 @ 07:10 PM CDT



echeewh 
Hi Shirley,
Following pls find my worked solutiion for Q1:
Q1.
Let number of children be u.
< 4u >
<10>
<130>
< 10u >
**********************< gap >
Using <Gap & Difference> technique, we have ...
10u  4u > 130  10
6u > 120
1u > 20
Number of Children = 20
====================
Trust this helps.
Do let me know again if this does not match your Answerkey or if there's any clarification.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 623



