Sign Up!
Login
Welcome to Test-paper.info
Tuesday, May 23 2017 @ 12:09 AM CDT
 Forum Index >  Test Paper Related >  Primary 5 Matters
 nan hua paper 2
   |  Printable Version
By: foresight (offline)  Monday, August 06 2012 @ 04:41 AM CDT (Read 890 times)  
foresight

Please help to solve these sums,thank you.
qn :12

Don had 4 times as much as money as Mei Mei.After he gave $9 to Mei Mei and spent $15 .Don and Mei Mei had the same amount of money.How much money did Don have at first ?

qn 13
The table shows thw number of students from 5 classess attending a camp.
: If all the students are grouped into teams of 5 students each, 1 student is left out.If they are grouped into the teams of 7 students each, 5 students are left out.What is the least number of students from class 5B ?

classess no of students campers
5A 33
5B ?
5C 25
5D 12
5E 7

Forum Newbie
Newbie

Registered: 05/30/10
Posts: 3

Profile Email    
   
By: GIM (offline)  Wednesday, August 08 2012 @ 09:37 AM CDT  
GIM

Q12

D |--------|--------|--------|--------|
|||||||||||||||||||||||||<--(-15)->|(-9-)|
M|---------|(+9)|

From the model,
3 units-----> 9 + 15 + 9 = 33
1 unit ------> 33 / 3 = 11
Don --------> 11 x 4 = $44 at first


Q13

Tabulate to find solution
Since the sum of pupils from other classes --> 33+25+12+7= 77, we should start with number greater than 77

Multiple of 5---> 80--85--90--95
(+1 left out) ---> 81--86--91--96

Multiple of 7---> 77--84--91
(+5 left out) ---> 82--89--96

common total is 96
therefore, pupils in class 5B---> 96 - 77 = 19

Forum Regular Member
Regular Member

Registered: 11/07/10
Posts: 70

Profile Email    
   


 All times are CDT. The time is now 12:09 am.
Normal Topic Normal Topic
Locked Topic Locked Topic
Sticky Topic Sticky Topic
New Post New Post
Sticky Topic w/ New Post Sticky Topic w/ New Post
Locked Topic w/ New Post Locked Topic w/ New Post
View Anonymous Posts 
Able to Post 
HTML Allowed 
Censored Content