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 By: csp (offline)  Thursday, August 09 2012 @ 06:13 AM CDT (Read 750 times)
csp

Hanson had some one-dollar coins and some fifty cents coins.the ratio of the number of one dollar coins to to number of fifty cent coins he had was 2:5. Hanson took 140 fifty cents coins to the bank and changed these fifty cents coins for the same value of one dollar coins.In the end ,the number of one dollar coins to the number of fifty cent coins he had became 5:2 ,
Find the value of the fifty cent coins Hanson had at first.

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Registered: 05/01/12
Posts: 4

 By: jo sarah (offline)  Thursday, August 09 2012 @ 09:21 AM CDT
jo sarah

hi,

first, the 140 fifty-cent coins = 70 one-dollar coins.

[i use ..... for spacing; 'u' means unit, and 'p' means part]

Now, tabulate the no. of coins as:
...................... \$1.................. 50 cts
at first:............2u...................5u
change:........(+70)..............(-140)
in end:.............5p..................2p
So,
2u + 70 = 5p
x2: 4u + 140 = 10p
5u - 140 = 2p
x5: 25u - 700 = 10p
thus, 4u + 140 = 25u - 700
that is, 21u = 840
and, 1u = 40
there were 5u = 200 fifty-cent coins at first.

So, value of fifty-cent coins at first = 200 x \$0.50 = \$100

Hope this helps,
cheerio.

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Registered: 03/20/12
Posts: 111

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