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 Forum Index >  Test Paper Related >  Primary 5 Matters 2011 Nanyang CA2 Maths Paper 2 Q13 & Q16
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 By: geniuskids (offline)  Monday, August 20 2012 @ 07:38 AM CDT (Read 1694 times)
geniuskids

Q16 : NY Primary School organised a 2-Day Charity FunFair. Admission tickets were sold to every visitor at a cost of \$40. On the first day, 120 more children visited the funfair than adults. The number of children on the second day was 25% more than the number of children on the first day. The number of adults on the second day was 5% less than the number of adults on the first day. There were a total of 2570 people at the funfair on the second day.
(a) Find the number of adults at the funfair on the first day.
(b) What was the total sum of money collected from the sale of the admisssion tickets for both days?

Q13 : There were 420 children in a childcare centre. 20% of the children were girls. Then some girls were enrolled into the childcare centre and the number of girls became 0.4 of the total number of children in the childcare centre. How many additional girls were enrolled into the childcare centre?

Kindly assist ASAP! Many thanks

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 By: GIM (offline)  Monday, August 20 2012 @ 10:43 AM CDT
GIM

Q13

Girls [__added__][___20%____] ~ (0.4)

Total [__added__][_____________420______________] ~ (1.0)

Girls at first : 20/100 x 420 = 84

0.6 ---------> 420 - 84 = 336
0.1 ---------> 336 รท 6 = 56
0.4 ---------> 56 x 4 = 224
Additional girls enrolled ---> 224 - 84 = 140

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Registered: 11/07/10
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 By: geniuskids (offline)  Tuesday, August 21 2012 @ 07:50 PM CDT
geniuskids

Thanks So much. But what about Q16???Anyone can help?

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Registered: 11/12/11
Posts: 169

 By: t0002630h (offline)  Wednesday, August 22 2012 @ 01:03 AM CDT
t0002630h

Q16
a) Assume the number of children on Day 1 is 100u + 120 and the number of adults is 100u. So on day 2, the number of children is 125u + 150 (25% more) and the number of adults is 95u (5% less). Total people on Day 2 is 220u + 150, which is also 2570. Thus 220u is 2570-150=2420. 1u is 2420/220=11. Adults on day 1 is 100u, so 100x11=1100.
b) Total people on both days --> 100u + 120 (children on day 1) + 100u (adults on day 1) + 220u + 150 (total people on day 2) = 420u + 270.
Total people on both days --> 420x11 + 270 = 4890.
Money collected --> 4890 x \$40 = \$195600.

Hope I helped

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 By: GIM (offline)  Wednesday, August 22 2012 @ 08:37 AM CDT
GIM

Q16 was asked by someone earlier. The solution is posted at "Primary 5 matters----math question------08/18/12 posted by TEOTECKWAH".

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Registered: 11/07/10
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