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By: tayangie (offline)  Thursday, September 06 2012 @ 12:54 AM CDT (Read 1574 times)  
tayangie

there were 1300 apples and pears in basket x and basket y. 30% of the 800 fruits in basket x were apples, 40% of the fruits in basket y were pears. After some fruits in both baskets were transferred from one to another, 25% of the fruits in basket x and 75% of the fruits in basket Y were apples. How many fruits were there in basket Y after transfer?

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By: echeewh (offline)  Thursday, September 06 2012 @ 06:06 PM CDT  
echeewh

Hey Angie,

Following pls find my worked solution :

Total (X + Y) = 1300
X = 800
A(X) = 30% x 800 = 240
P(X) = 800 - 240 = 560

Y = 500
P(Y) = 40% x 500 = 200
A(Y) = 500 - 200 = 300

** - for alignment purpose


<Before>
*** X ************* Y
A **** P ****** A *** P
240 : 560 *** 300 : 200

<Process>
some fruits in both baskets were transferred from one to another

<After>
** X ********* Y
A ** P ***** A ** P
25 : 75 *** 75 : 25
* 1 : 3 ******* 3 : 1

Using <Unchanged Total> concept, total number of A in X,Y (After> = total number of A in X,Y <Before>. Likewise for number of P in X,Y.

Using Simultaneous method, let the <After> ratio in X be part (p) qtys, and the <After> ratio in Y be unit (u) qtys, and we have ...

1p + 3u --> 240 + 300 = 540 -- (1)
3p + 1u --> 560 + 200 = 760 -- (2)

To find number of fruits in basket Y after transfer, we need to find the unit (u) qty, while eliminating the part (p) qty.

Eliminating (p), we have ...
(1)x3: 3p + 9u --> 1620 -- (3)

Comparing (3) and (2):
(3)-(2): 9u - 1u --> 1620 - 760
8u --> 860
1u --> (860/8)

Total number of fruits in Y (after transfer) = 4u
4u --> 4 x (860/8) = 430

=======================

Do let me know again if the answer does not match your Answerkey or if there's further clarification.

Btw which sch prelimpaper is this??

Cheers,
Edward

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By: tayangie (offline)  Tuesday, September 11 2012 @ 08:57 AM CDT  
tayangie

This is Mayflower primary school perlimpaper.

Thanks for replying

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