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Wednesday, June 28 2017 @ 02:00 AM CDT
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 Maths Question 28
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By: shirley wee (offline)  Thursday, September 06 2012 @ 03:01 AM CDT (Read 591 times)  
shirley wee

1) Gary is paid $4.80 to assemble4 a toy car. He also receives an additional $6.60 for every 8 toy cars that he assembles. If Gary received a total of $253.80 this month, how many toy cars did he assemble?

2) Farid had $270 and Gopal had $192. Gopal spent twice as much as Farid. If Farid had twice as much money as Gopal after spending, how much did Farid spend?

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By: echeewh (offline)  Monday, October 22 2012 @ 10:56 PM CDT  
echeewh

Hey Shirley

Following pls find my worked solutions:

Q1.

Apply <Grouping> method,

Group of 8 = (4.80 × 8) + 6.60 = 45
253.80 ÷ 45 = 5.64 ==> 5 groups of 8 = 40
Remaining money = 0.64 x 45 = 28.80
28.80 ÷ 4.80 = 6
Number of toy cars assembled = 40 + 6 = 46


Q2.

<after>

F |---------|---------| --> 2u
G |---------| --> 1u

<work backwards>
F: + 1p spent
G: + 2p spent

**<------- 270 ------->
F |---------|---------|--| --> 2u + 1p
G |---------|--|--| --> 1u + 2p
**<--- 192 ---->

Applying <Simultaneous> method, we have ...

2u + 1p --> 270 -- (1)
1u + 2p --> 192 -- (2)

To calculate how much F spent, eliminate (u).

(2)x2:
2u + 4p --> 384 -- (3)

(3)-(1):
4p - 1p --> 384 - 270
3p --> 114
1p --> 38

F spent = 1p --> $38

=====================

Trust these help.

Do let me know again if the answers are different from your Answerkey or if there's further clarification.

Cheers,
Edward

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