Hey Shirley

Following pls find my worked solutions:

Q1.

Apply <Grouping> method,

Group of 8 = (4.80 × 8) + 6.60 = 45

253.80 ÷ 45 = 5.64 ==> 5 groups of 8 = 40

Remaining money = 0.64 x 45 = 28.80

28.80 ÷ 4.80 = 6

Number of toy cars assembled = 40 + 6 = **46**

Q2.

<after>

F |---------|---------| --> 2u

G |---------| --> 1u

<work backwards>

F: + 1p spent

G: + 2p spent

**<------- 270 ------->

F |---------|---------|--| --> 2u + 1p

G |---------|--|--| --> 1u + 2p

**<--- 192 ---->

Applying <Simultaneous> method, we have ...

2u + 1p --> 270 -- (1)

1u + 2p --> 192 -- (2)

To calculate how much F spent, eliminate (u).

(2)x2:

2u + 4p --> 384 -- (3)

(3)-(1):

4p - 1p --> 384 - 270

3p --> 114

1p --> 38

F spent = 1p --> **$38**

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Trust these help.

Do let me know again if the answers are different from your Answerkey or if there's further clarification.

Cheers,

Edward