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 By: geniuskids (offline)  Tuesday, October 16 2012 @ 02:51 AM CDT (Read 1002 times)
geniuskids

Q16 : Mr Chen bought some pencil cases and bags for the children at a gathering.
The price of each pencil case was \$2.40 while the price of each bag was \$10.80.
For every 4 bags bought, he was given one such pencil case for free.
After receiving the free pencil cases, the number of pencil cases was 1/3 of the number of bags bought.
If Mr Mr Chen paid a total of \$1584, how much more did he pay for the bags than the pencil cases?

Thanks

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Registered: 11/12/11
Posts: 169

 By: echeewh (offline)  Saturday, October 20 2012 @ 07:51 PM CDT
echeewh

Hey there,

Following pls find my worked solution:

<after> receiving free pencil cases (PC),

PC : B
1 : 3

Given that for every 4 B bought, 1 PC was given free, multiply ratio 4x. (to make B multiple of 4)

PC : B
4 : 12

Apply <Restating the problem> method, we have ..
for 12u of B bought --> 3 free PC

PC(bought) : PC (free) : B
1 : 3 : 12

Since total amt paid = \$1584 and 1 PC = \$2.40 and 1 B = \$10.80, we apply <Number × Value> method as shown:

(1u × 240) + (12u × 1080) --> 158400
240u + 12960u --> 158400
13200u --> 158400
1u --> 1584 ÷ 132 = 12

PC (bought) = 1u --> 12
Value of PC: 12 × 2.40 = \$28.80

B = 12u --> 12 × 12 = 144
Value of B: 144 × 10.80 = \$1555.20

Value of (B - PC) = \$1555.20 - \$28.80 = \$1526.40

=====================

Trust this helps.

Do let me know again if there's any clarification.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

 By: geniuskids (offline)  Saturday, October 20 2012 @ 08:49 PM CDT
geniuskids

Thanks Edward. You have been a great hep. Do you mind helping with Q17 Nanyang. Tx

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Registered: 11/12/11
Posts: 169

 By: geniuskids (offline)  Saturday, October 20 2012 @ 09:06 PM CDT
geniuskids

latest update: Q17 solved. tks

Active Member

Registered: 11/12/11
Posts: 169

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