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 Forum Index >  Test Paper Related >  Primary 5 Matters P5 Maths 2011 SA2 MGS Paper 1 Q5 & Q11
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 By: geniuskids (offline)  Tuesday, October 16 2012 @ 03:57 AM CDT (Read 948 times)
geniuskids

Hi, pls help solve the questions:-

Q5 : Please refer to the diagram on the test paper.

A and B are mid-points of the sides of the rectangle
What fraction of the rectangle is shaded?

(1) 1/4
(2) 3/8
(3) 5/8
(4) 3/4

Q11 : The avearge mass of a group of boys was 48kg.
When John joined the group, the new average mass of the group became 54kg.
If John weighed 72kg, how many boys were there in the group in the end?
(1) 9
(2) 8
(3) 6
(4) 4

Active Member

Registered: 11/12/11
Posts: 169

 By: geniuskids (offline)  Saturday, October 20 2012 @ 09:33 PM CDT
geniuskids

Hi there,

Q5 : managed to solved. quite simple. tks
Q11 : my solution : 54-48 = 6
72÷6=12
48÷12=4
The answer is (4) 4, which we managed to get but don't really understand. Someone pls hep explain. Tks

Active Member

Registered: 11/12/11
Posts: 169

 By: EMY (offline)  Sunday, October 21 2012 @ 03:37 AM CDT
EMY

Hi Q11 - don't know how to explain your working. Anyway, mine is:

if A = original number of people
and B = new number of people = A+1 (after John joins); then:

48A + 72 (John's mass) = 54B

so replacing B=A+1, it becomes:
48A + 72 = 54A + 54
6A = 18
A = 3

finally B = 3 + 1 = 4

Newbie

Registered: 10/21/10
Posts: 5

 By: geniuskids (offline)  Sunday, October 21 2012 @ 03:47 AM CDT
geniuskids

hi, thanks for helping but yr method seems "complicated" for a P5.
I'll try to understand.
Thanks again

Active Member

Registered: 11/12/11
Posts: 169

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