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 P5 Maths 2011 SA2 ACS Paper 2 Q18
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By: geniuskids (offline)  Sunday, October 21 2012 @ 04:36 AM CDT (Read 592 times)  
geniuskids

Q18 : Mrs Ho had 2 boxes of oranges. At first, there are 228 more oranges in Box A than in Box B.
Mrs Ho then transfers 600 oranges from Box A to Box B.
Now, Box B contained 5 times as many oranges as Box A. How many oranges are there in each box at first?

Someone pls help!
Tks

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By: echeewh (offline)  Sunday, October 21 2012 @ 08:25 PM CDT  
echeewh

Hey there,

You can just apply the usual <Before> and <After> model concept together with <Gap & Difference> technique, and it will work Big Grin

Anyway, heres how to do it ....

<before>

A |-----------|<228>|
B |-----------|

<process>

600 oranges transferred from A to B.
600 - 228 = 372

<After>

** <1u>
A |--|<-372-><228>|
B |-----------<--- 600 -->|
** <---------- 5u ---------->

Apply <Gap & Difference> method, we have ...

5u - 1u --> 372 + 600
4u --> 972
1u --> 243

Oranges in A (at first) = 1u + 600 --> 243 + 600 = 843
Oranges in B (at first) = 843 - 228 = 615

========================

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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