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 By: Tping (offline)  Wednesday, October 24 2012 @ 07:12 PM CDT (Read 911 times)
Tping

Hi,

1)
A vase cost \$25. A bowl cost \$6 cheaper.
A customer paid \$1410 for some vases and bowls.
He bought thrice as many vases as bowl.
a) how many vases did he buy?
b) How much more money did he spend on the vases than bowls.

2)
A florist sold twice as many roses as tulips and collected \$400 in total.
She collected \$80 more on the tulips than roses.
Given that a tulip costs \$2 more than a rose,
find the cost of a rose.

Junior

Registered: 01/26/12
Posts: 25

 By: echeewh (offline)  Wednesday, October 24 2012 @ 10:52 PM CDT
echeewh

Hi Tping,

By now this is another typical question making use of <Number x Value> method to do.

If you have been following the questions and posts lately, you would have seen this method being used a number of times. Anyway, here goes my worked solution.

Q1.

<Number/Qty>
V : B
3 : 1

V = \$25; B = \$19

Apply <Number x Value> method, we have ...

(3u × 25) + (1u × 19) --> 1410
75u + 19u --> 1410
94u --> 1410
1u --> 15

(a)
Vases = 3u --> 3 × 15 = 45

(b)
Money spent: V - B = 75u - 19u = 56u
56u --> 56 × 15 = \$840

========================

Q2. ( Posted 25/10, 14:30)

<Qty>
R : T
2 : 1

<value>

R |---------|
T |---------<-80->|

Total Value (R + T) = 400
Value (R) = (400 - 80) ÷ 2 = 160
Value (T) = 160 + 80 = 240

2u (R) --> 160
1u (R) --> 80
1u (T) --> 240

Difference in value = [1u (T)] - [1u (R)]
= 240 - 80 = 160

Given that tulip costs \$2 more than a rose,

Value (T - R) = 2 ,

Number of 1u (T/R) = 160 ÷ 2 = 80

Hence, number of R = 160; T = 80

Hence, cost of a Rose (R) = 160 ÷ 160 = \$1

========================

Trust this helps .

Do let me know again if this is different from your Answerkey or if there's further clarification.

Cheers and all the very best,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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