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 By: shirley wee (offline)  Friday, November 02 2012 @ 08:38 AM CDT (Read 691 times)
shirley wee

Hi everyone! I am stuck with this math question. Can you help me? Please show your workings clearly.

Qn1. There are 153 pupils in the school choir and the Chinese dance group. When 3/5 of the the dance group members and 5/6 of the choir members left to attend a competition, an equal number of members in the two groups remained in school. How many members are there in the choir?

Chatty

Registered: 02/28/12
Posts: 68

 By: echeewh (offline)  Friday, November 02 2012 @ 07:02 PM CDT
echeewh

hey shirley,

Following pls find my worked solution:

Apply <work backwards> method by model:

<After>

C |------|------|
D |------|------|

<Process>
(3/5)D left; so (2/5)D remains;
in <after> model for D, split into 2 equal parts; likewise for moded C.
in <before>model,
D: +3 parts
C: (1/6) remains --> 2parts
(6/6) --> 12parts

<Before>

C |------|------|------|------|------|------|------|------|------|------|------|------|
D |------|------|------|------|------|

Given that (C+D) = 153, we have ...

12u + 5u --> 153
17u --> 153
1u --> 9

C = 12u --> 12 × 9 = 108

==================

trust this helps.

Do let me know again if this is different from your Answerkey, or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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