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 By: shirley wee (offline)  Friday, November 02 2012 @ 09:16 AM CDT (Read 1393 times)
shirley wee

Hi everyone! I am stuck with this maths question. May you help me? Please show your workings clearly.

Qn1. Shawn had 2/7 as much money as Keith. After Keith gave \$1596 to Shawn, he had 1/2 as much as Shawn. How much did they have altogether?

Chatty

Registered: 02/28/12
Posts: 68

 By: echeewh (offline)  Friday, November 02 2012 @ 07:55 PM CDT
echeewh

Hi Shirley,

Following pls find my worked solution:

<Before>

S : K total
2 : 7 9 -- (1)

<Process>
K: -1596
S: +1596

<After>

S : K total
2 : 1 3 -- (2)

Apply <Unchanged Total> concept (i.e. total money before = total money after), multiply (2) 3x.

hence,

<After>

S : K total
6 : 3 9

Given that K gave \$1596 to S, we have ...

K:
7u - 3u --> 1596
4u --> 1596
1u --> 399

S+K (at first) = 9u --> 9 × 399 = \$3591

========================

Trust this helps.

Do let me know again if this is different from your Answerkey or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: Zoena86 (offline)  Tuesday, November 13 2012 @ 07:31 AM CST
Zoena86

Shawn : Keith
2 : 7 x 2 = 14
+1596 - 1596 x 2 = 3192
2 : 1 x 2 = 2

Method:

2u + 1596 = 14u - 3192
1596 + 3192 = 14u - 2u
4788 = 12u
399 = 1u
3591 = 9u

Newbie

Registered: 08/18/09
Posts: 2

 By: Zoena86 (offline)  Tuesday, November 13 2012 @ 07:31 AM CST
Zoena86

Shawn : Keith
2 : 7 x 2 = 14
+1596 - 1596 x 2 = 3192
2 : 1 x 2 = 2

Method:

2u + 1596 = 14u - 3192
1596 + 3192 = 14u - 2u
4788 = 12u
399 = 1u
3591 = 9u

Newbie

Registered: 08/18/09
Posts: 2

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