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 Forum Index >  Test Paper Related >  Primary 5 Matters
 Math Question 38
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By: jp odell (offline)  Wednesday, November 07 2012 @ 03:22 AM CST (Read 727 times)  
jp odell

Hi,

Anyone can help on the attached Question Number 8. This question involved with diagram, therefore I need to attach.

Qn 8. The figure below is a rectangle. Find the shaded area.

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By: echeewh (offline)  Wednesday, November 07 2012 @ 08:00 PM CST  
echeewh

Hey there,

Following pls find my worked solution:

Q8.

Area of triangle = (B x H) / 2

in given figure, label triangle A (90 cm2), B (70 cm2), C (30 cm2), D (shaded).

Area of triangles (A + C) = [B x (sum of perpendicular heights of A,C)] / 2
= (B x L) /2 = (1/2) of Rectangle (since B is common and sum of perpendicular heights is L(ength))
= 90 + 30 = 120 cm2

Hence, shaded area (D) = 120 - 70 = 50 cm2

==================

Trust this helps.

Do let me know if this is different from your Answerkey or if there's further clarification.

Cheers,
Edward

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