Sign Up!
Login
Welcome to Test-paper.info
Sunday, April 30 2017 @ 12:04 AM CDT
 Forum Index >  Test Paper Related >  Primary 5 Matters
 Maths Question 38
   |  Printable Version
By: shirley wee (offline)  Saturday, November 17 2012 @ 08:00 PM CST (Read 623 times)  
shirley wee

Hi everybody! I'm stuck with this maths question. May you help me? Please show your working clearly.

Qn1. Alan had $360 more than Clive. After Alan spent half of the amount he had, the ratio of the amount of Alan's money to Clive's became 3 : 2.
(a) How much money did Alan have left after spending half of his money?
(b) Alan later gave Clive some money so that the ratio became 8 : 7. How much money did Alan give Clive?

Thank you for your help.

Forum Chatty
Chatty

Registered: 02/28/12
Posts: 68

Profile Email    
   
By: echeewh (offline)  Sunday, November 18 2012 @ 07:04 PM CST  
echeewh

Hey shirley,

Following pls find my worked solution:

<after>

A : C
3 : 2

using <work backwards> method and since these 3u left of A are (1/2) of what A had originally, we have ...

<before>

A : C
6 : 2

Givent that A - C = 360, we have ...

6u - 2u --> 360
4u --> 360
1u --> 90

(a)
A (left) = 3u --> 3 × 90 = $270

(b)

<before>
A : C
3 : 2

<before> total = A + C = 5u --> 5 × 90 = $450

<after>

A : C
8 : 7

Apply <Unchanged Total> concept, we have ...

<after> A + C = 8p + 7p = 15p --> 450
1p --> 30

A (after) = 8p --> 8 × 30 = 240

A gave C = A (before) - A (after)
= 270 - 240 = $30


==============================

Trust this helps.

Do let me know again if this is different from your answerkey or if there's further clarification.

Cheers,
Edward

Forum Active Member
Active Member

Registered: 04/21/11
Posts: 623

Profile Email    
   


 All times are CDT. The time is now 12:04 am.
Normal Topic Normal Topic
Locked Topic Locked Topic
Sticky Topic Sticky Topic
New Post New Post
Sticky Topic w/ New Post Sticky Topic w/ New Post
Locked Topic w/ New Post Locked Topic w/ New Post
View Anonymous Posts 
Able to Post 
HTML Allowed 
Censored Content