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 By: shirley wee (offline)  Saturday, November 17 2012 @ 08:08 PM CST (Read 963 times)
shirley wee

Hi everybody! I'm stuck with this maths question. May you help me? Please show your working clearly.

Qn1. Justin spent 3/10 of his money an 11 packs of cards. He would be able to buy another 29 packs of cards with his remaining amount of money and an additional \$20. (a) What was the price of one pack of cards? (b) How much money did Justin have at first?

Chatty

Registered: 02/28/12
Posts: 68

 By: echeewh (offline)  Sunday, November 18 2012 @ 07:31 PM CST
echeewh

hi shirley,

Following pls find my worked solution:

(a)

(3/10)total --> 11 packs
(7/10)total --> (11/3) × 7 = (77/3)

(7/10)total + \$20 --> 29 packs
(77/3) packs + \$20 --> 29 packs
[29 - (77/3)] --> \$20
[(87 - 77) / 3] --> \$20
(10/3) --> \$20
10 packs --> \$60
1 pack = \$6

(b)

(3/10)total --> 11 packs = 11 × 6 = \$66
(10/10)total --> 66 ÷ (3/10) = 66 × (10/3) = 220

==============

Trust this helps.

Do let me know again if this is different from your answerkey or if theres further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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