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Friday, July 21 2017 @ 03:44 PM CDT
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 Maths Question 39
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By: shirley wee (offline)  Saturday, November 17 2012 @ 08:08 PM CST (Read 926 times)  
shirley wee

Hi everybody! I'm stuck with this maths question. May you help me? Please show your working clearly.

Qn1. Justin spent 3/10 of his money an 11 packs of cards. He would be able to buy another 29 packs of cards with his remaining amount of money and an additional $20. (a) What was the price of one pack of cards? (b) How much money did Justin have at first?

Thank you for your help.

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By: echeewh (offline)  Sunday, November 18 2012 @ 07:31 PM CST  
echeewh

hi shirley,

Following pls find my worked solution:

(a)

(3/10)total --> 11 packs
(7/10)total --> (11/3) × 7 = (77/3)

(7/10)total + $20 --> 29 packs
(77/3) packs + $20 --> 29 packs
[29 - (77/3)] --> $20
[(87 - 77) / 3] --> $20
(10/3) --> $20
10 packs --> $60
1 pack = $6

(b)

(3/10)total --> 11 packs = 11 × 6 = $66
(10/10)total --> 66 ÷ (3/10) = 66 × (10/3) = 220

At first, Justin had $220

==============

Trust this helps.

Do let me know again if this is different from your answerkey or if theres further clarification.

Cheers,
Edward

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