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 By: Rohana (offline)  Wednesday, December 12 2012 @ 01:36 AM CST (Read 971 times)
Rohana

Q16. There are some oranges in 3 boxes, A, B and C. 40% of the number of oranges in
Box A is equal to 25% of the number of oranges in Box B. The number of oranges
In Box C is 50% of the number of oranges in Box B.
a. Express the number of oranges in Box C as a fraction of the number of oranges in Box A.
b. When 40% of the oranges in Box A are taken out and placed in Box C, there will be 36
oranges left in box A. How many oranges are there in Box B?

Can anyone pls help me with this problem sum. Thks!

Junior

Registered: 01/24/12
Posts: 18

 By: echeewh (offline)  Wednesday, December 12 2012 @ 04:18 AM CST
echeewh

Hi Rohana,

Following pls find my worked solution:

40% A = 25% B
(2/5) A = (1/4) B

Apply Equal concept here {make numerator of fractions in both A,B the same}

(2/5) A = (2/8) B

Hence, A = 5u; B = 8u

Given oranges in C is 50% of that in B,
C = 4u

(a)
(C / A) = 4/5

(b)
40% of the oranges in Box A are taken out = (2/5) × 5u = 2u

Hence, 3u oranges are left in A.

Given 36 oranges are left in box A, we have ...
3u --> 36
1u --> 12

Number of Oranges in B = 8u --> 8 × 12 = 96

===========

Trust this helps.

Do let me know again if this is different from your Answerkey or if there's further clarification.

Cheers,
Edward.

Active Member

Registered: 04/21/11
Posts: 627

 By: Rohana (offline)  Wednesday, December 12 2012 @ 04:24 AM CST
Rohana

Thanks Edward!

Junior

Registered: 01/24/12
Posts: 18

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