
By: Rohana (offline) Wednesday, December 12 2012 @ 01:36 AM CST (Read 947 times)



Rohana 
Q16. There are some oranges in 3 boxes, A, B and C. 40% of the number of oranges in
Box A is equal to 25% of the number of oranges in Box B. The number of oranges
In Box C is 50% of the number of oranges in Box B.
a. Express the number of oranges in Box C as a fraction of the number of oranges in Box A.
b. When 40% of the oranges in Box A are taken out and placed in Box C, there will be 36
oranges left in box A. How many oranges are there in Box B?
Can anyone pls help me with this problem sum. Thks!

Junior
Registered: 01/24/12 Posts: 18





By: echeewh (offline) Wednesday, December 12 2012 @ 04:18 AM CST



echeewh 
Hi Rohana,
Following pls find my worked solution:
40% A = 25% B
(2/5) A = (1/4) B
Apply Equal concept here {make numerator of fractions in both A,B the same}
(2/5) A = (2/8) B
Hence, A = 5u; B = 8u
Given oranges in C is 50% of that in B,
C = 4u
(a)
(C / A) = 4/5
(b)
40% of the oranges in Box A are taken out = (2/5) × 5u = 2u
Hence, 3u oranges are left in A.
Given 36 oranges are left in box A, we have ...
3u > 36
1u > 12
Number of Oranges in B = 8u > 8 × 12 = 96
===========
Trust this helps.
Do let me know again if this is different from your Answerkey or if there's further clarification.
Cheers,
Edward.

Active Member
Registered: 04/21/11 Posts: 627





By: Rohana (offline) Wednesday, December 12 2012 @ 04:24 AM CST



Rohana 
Thanks Edward!

Junior
Registered: 01/24/12 Posts: 18



