Welcome to Test-paper.info
Thursday, January 18 2018 @ 03:56 PM CST
 Select a Forum » General Chat » Primary 1 Matters » Primary 2 Matters » Primary 3 Matters » Primary 4 Matters » Primary 5 Matters » Primary 6 Matters » Question, Feedback and Comments » Education Classified
 Forum Index >  Test Paper Related >  Primary 6 Matters Angles in Geometric Figures
 | Printable Version
 By: Rohana (offline)  Monday, January 07 2013 @ 03:26 AM CST (Read 814 times)
Rohana

Hi, can anyone help me to solve the maths question attached.

Junior

Registered: 01/24/12
Posts: 18

 By: echeewh (offline)  Wednesday, January 09 2013 @ 03:51 AM CST
echeewh

Hey Rohana,

Following pls find my worked solution :

Angle CDE = 78° = Angle BAD {corresponding angle}
Angle DCE = (180 - 78) ÷ 2 = 51°
Angle x = 180 - 51 = 129°

Referring to 4-sided figure FBAD {sum of interior angles = 360°},

Angle BAD = 360 - 78 = 282°
Angle ADF = 180 - 150 = 30°
Angle y = 360 - 282 - 30 - 36 = 12°

===========

Trust this helps..

Do let me know again if there's any clarification.

Cheers,
Edward.

Active Member

Registered: 04/21/11
Posts: 627

 All times are CST. The time is now 03:56 pm.
 Normal Topic Locked Topic Sticky Topic
 New Post Sticky Topic w/ New Post Locked Topic w/ New Post
 View Anonymous Posts Able to Post HTML Allowed Censored Content