
By: achieve_goal (offline) Saturday, March 02 2013 @ 12:21 AM CST (Read 1112 times)



achieve_goal 
pls find the attached(scanned) documents. They are the questions...

Regular Member
Registered: 09/14/11 Posts: 102





By: nisalam (offline) Saturday, March 02 2013 @ 08:25 PM CST



nisalam 
q1
After: foreign coins = 5u, local coins = 2p
Before: foreign coins = 10u, local coins = 10p
10u + 10p = 560
5u + 2p = 172 ? 10u + 4p = 344
Solving the equations, 6p = 216
1p = 36
(a) Local coins at first = 36 * 10 = 360
(b) 560 – 360 = 200
Foreign coins given away = 100

Junior
Registered: 04/29/10 Posts: 30





By: echeewh (offline) Monday, March 04 2013 @ 04:53 AM CST



echeewh 
Hi there,
Following pls find my worked solution for Q2:
***  alignment purpose
Q2
<After>
T : R : C
6 : 5 *****  (1)
*** 7 : 3 **  (2)
Using <Repeated Identity> concept, multiply (1) 7x, (2) 5x and we have ...
T : R : C
42 : 35
**** 35 : 15
(a)
Given that 456 T,C were left after selling 168 R.
T + C = 456
42u + 15u > 456
57u > 456
1u > 8
R (left) = 35u > 35 × 8 = 280
R (at first) = 280 + 168 = 448
(b)
Given that an equal/same number of T and C were sold, the difference between T and C (before and after) remains the same {<Unchanged Difference> concept}. We now have ...
<After>
T : C **** Diff
42 : 15 ** 27  (3)
<before>
T : C
2 : 1 ***** 1  (4)
(4)x27:
54 : 27 ** 27
Hence,
T (sold) = 54u  42u = 12u
C (sold) = 27u  15u = 12u
T + C (sold) = 12u + 12u = 24u > 24 × 8 = 192
=================
Trust this helps.
Do let me know again if this is different from your Answerkey or if theres further clarification.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: achieve_goal (offline) Tuesday, March 05 2013 @ 07:10 AM CST



achieve_goal 
Thank you very much!

Regular Member
Registered: 09/14/11 Posts: 102



