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 By: achieve_goal (offline)  Saturday, March 02 2013 @ 12:21 AM CST (Read 1129 times)
achieve_goal

pls find the attached(scanned) documents. They are the questions...

Regular Member

Registered: 09/14/11
Posts: 102

 By: nisalam (offline)  Saturday, March 02 2013 @ 08:25 PM CST
nisalam

q1

After: foreign coins = 5u, local coins = 2p
Before: foreign coins = 10u, local coins = 10p
10u + 10p = 560
5u + 2p = 172 ? 10u + 4p = 344
Solving the equations, 6p = 216
1p = 36
(a) Local coins at first = 36 * 10 = 360
(b) 560 – 360 = 200
Foreign coins given away = 100

Junior

Registered: 04/29/10
Posts: 30

 By: echeewh (offline)  Monday, March 04 2013 @ 04:53 AM CST
echeewh

Hi there,

Following pls find my worked solution for Q2:

*** - alignment purpose

Q2

<After>

T : R : C
6 : 5 ***** -- (1)
*** 7 : 3 ** -- (2)

Using <Repeated Identity> concept, multiply (1) 7x, (2) 5x and we have ...

T : R : C
42 : 35
**** 35 : 15

(a)

Given that 456 T,C were left after selling 168 R.

T + C = 456
42u + 15u --> 456
57u --> 456
1u --> 8

R (left) = 35u --> 35 × 8 = 280
R (at first) = 280 + 168 = 448

(b)
Given that an equal/same number of T and C were sold, the difference between T and C (before and after) remains the same {<Unchanged Difference> concept}. We now have ...

<After>
T : C **** Diff
42 : 15 ** 27 -- (3)

<before>
T : C
2 : 1 ***** 1 -- (4)

(4)x27:
54 : 27 ** 27

Hence,
T (sold) = 54u - 42u = 12u
C (sold) = 27u - 15u = 12u

T + C (sold) = 12u + 12u = 24u --> 24 × 8 = 192

=================

Trust this helps.

Do let me know again if this is different from your Answerkey or if theres further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: achieve_goal (offline)  Tuesday, March 05 2013 @ 07:10 AM CST
achieve_goal

Thank you very much!

Regular Member

Registered: 09/14/11
Posts: 102

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