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 By: rctw1989 (offline)  Saturday, March 02 2013 @ 08:32 PM CST (Read 836 times)
rctw1989

Hi

Your help to this question is appreciated. Tks

Alan had 1500 ml of white paint in Tin A and 1250 ml of blue paint in Tin B. Alan poured 750 ml of blue paint from Tin B to Tin A. Subsequently he poured some of the mixture in Tin A back into Tin B. If 7/11 of the final mixture in Tin B was blue paint, what was the volume of the mixture in Tin A that Alan had poured into Tin B (ans 600 ml)

Newbie

Registered: 12/31/12
Posts: 3

 By: echeewh (offline)  Monday, March 04 2013 @ 10:39 PM CST
echeewh

Hi there,

Appreciate that you put your question in Forums -> Test Paper Related -> Primary 6 Matters.

Following pls find my worked solution:

<before>
Tin A (mixture)
W : B
1500 : 750
2 : 1

Tin B:
500 ml (B )

<some mixture from A was poured into B>

<after>
Tin B (mixture)
W : B
4 : 7

Let the <before> ratio be parts(p) and <after> be units(u). We now have ...

W: 2p + 0 = 4u
B: 1p + 500 = 7u

Rearranging these ...

4u - 2p = 0 -- (1)
7u - 1p = 500 -- (2)

(2)x2:
14u - 2p = 1000 -- (3)

(3)-(1):
14u - 4u --> 1000
10u --> 1000
1u --> 100

Tin B (mixture) (after) = 11u --> 11 × 100 = 1100 ml

Hence, volume of Tin A (mixture) poured into Tin B = 1100 - 500
= 600 ml

================

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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