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 By: Tping (offline)  Thursday, March 28 2013 @ 07:58 AM CDT (Read 723 times)
Tping

Hi, please help..

Peter has a box that can hold either 48 big buns or 60 small buns.
There are already 12 big buns and 10 small buns in the box.
What is the maximum number of big buns the box can still hold?

Thank you.

Junior

Registered: 01/26/12
Posts: 25

 By: echeewh (offline)  Thursday, March 28 2013 @ 11:14 PM CDT
echeewh

Hey Tping,

Following pls find my worked solution :

60S = 48B
10S = 8B

this infers the box contains 12B and an equivalent of 8B buns. Hence , an equivalent of 20B buns in the box.

Given the box can hold 48B, the max number of big buns it can still hold is ...

48 - 20 = 28

============

Trust this helps.

Do let me know again if this is different from your Answerkey or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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