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Thursday, June 22 2017 @ 05:28 PM CDT
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By: achieve_goal (offline)  Sunday, April 28 2013 @ 02:51 AM CDT (Read 736 times)  
achieve_goal

Hi, anybody help this questions,

Aminda bought some red, yellow and blue beads to make a necklace. 1/6 of the yellow beads were
equal to 3/4 of the red beads.The number of blue beads was 5/11 of the total number of red and
yellow beads. If there were 54 more blue beads than red beads, how many beads did Aminda buy altogether?



2}Q
Nicole received more money than Tricia from their mother. 40% of Tricia s money is $16 less
than25% of Nicole's money. If Nicole gives 35% of her money to Tricia, Nicole will have $12
less than Tricia.

a] How much money does Tricia has?

b} How many percent more money does Nicole has than Tricia at first?
Round off your answers to the nearest 2 decimal places.

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By: echeewh (offline)  Sunday, April 28 2013 @ 08:19 PM CDT  
echeewh

Hey achieve_goal,

Following pls find my worked solution:

Q1

(1/6)Y = (3/4)R

Apply <Equal Concept> method, make numerator of both fractions same. So multiply left-side fraction (3/3).

(3/18)Y = (3/4)R

Hence, Y = 18u; R = 4u

Alternatively, can also use <Comparison model> technique to determine the starting units for both Y and R.

Total (R + Y) = 22u
Hence, B = (5/11) × 22 = 10u

Given that there were 54 more blue beads than

red beads, we have ...

B - R = 54
10u - 4u --> 54
6u --> 54
1u --> 9

Total beads (R + Y + B ) = 22u + 10u = 32u

32u --> 32 × 9 = 288

===========

Q2

25% N = 40% T + $16
100% N = 160% T + $64

<Before>
N: 160u + 64
T: 100u

<process>
35% N = 56u + $22.40
This (35% N) is given to T.

<After>
N: 104u + 41.60
T: 156u + 22.40

Given that Nicole (N) will have $12 less than Tricia (T), we have ...

T - N = 12
156u + 22.40 - 104u - 41.60 = 12.00
52u --> 31.20
1u --> 0.60

(a)
T (at first) = 100u
100u --> 100 × 0.60 = $60

(b)
N - T (at first) = 160u + 64 - 100u = 60u + 64
60u + 64 --> (60 × 0.60) + 64 = 36 + 64 = 100

% more than T = (100 / 60) × 100 ~ 166.67% (to 2 dec places)

============

Trust the above helps.

Do let me know again if this is different from your Answerkey or if there's further clarification.

Cheers,
Edward

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By: achieve_goal (offline)  Monday, April 29 2013 @ 10:32 PM CDT  
achieve_goal

Hi,
Edward thank you.now i understand that maths questions.

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