
By: achieve_goal (offline) Sunday, April 28 2013 @ 02:51 AM CDT (Read 770 times)



achieve_goal 
Hi, anybody help this questions,
Aminda bought some red, yellow and blue beads to make a necklace. 1/6 of the yellow beads were
equal to 3/4 of the red beads.The number of blue beads was 5/11 of the total number of red and
yellow beads. If there were 54 more blue beads than red beads, how many beads did Aminda buy altogether?
2}Q
Nicole received more money than Tricia from their mother. 40% of Tricia s money is $16 less
than25% of Nicole's money. If Nicole gives 35% of her money to Tricia, Nicole will have $12
less than Tricia.
a] How much money does Tricia has?
b} How many percent more money does Nicole has than Tricia at first?
Round off your answers to the nearest 2 decimal places.

Regular Member
Registered: 09/14/11 Posts: 102





By: echeewh (offline) Sunday, April 28 2013 @ 08:19 PM CDT



echeewh 
Hey achieve_goal,
Following pls find my worked solution:
Q1
(1/6)Y = (3/4)R
Apply <Equal Concept> method, make numerator of both fractions same. So multiply leftside fraction (3/3).
(3/18)Y = (3/4)R
Hence, Y = 18u; R = 4u
Alternatively, can also use <Comparison model> technique to determine the starting units for both Y and R.
Total (R + Y) = 22u
Hence, B = (5/11) × 22 = 10u
Given that there were 54 more blue beads than
red beads, we have ...
B  R = 54
10u  4u > 54
6u > 54
1u > 9
Total beads (R + Y + B ) = 22u + 10u = 32u
32u > 32 × 9 = 288
===========
Q2
25% N = 40% T + $16
100% N = 160% T + $64
<Before>
N: 160u + 64
T: 100u
<process>
35% N = 56u + $22.40
This (35% N) is given to T.
<After>
N: 104u + 41.60
T: 156u + 22.40
Given that Nicole (N) will have $12 less than Tricia (T), we have ...
T  N = 12
156u + 22.40  104u  41.60 = 12.00
52u > 31.20
1u > 0.60
(a)
T (at first) = 100u
100u > 100 × 0.60 = $60
(b)
N  T (at first) = 160u + 64  100u = 60u + 64
60u + 64 > (60 × 0.60) + 64 = 36 + 64 = 100
% more than T = (100 / 60) × 100 ~ 166.67% (to 2 dec places)
============
Trust the above helps.
Do let me know again if this is different from your Answerkey or if there's further clarification.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: achieve_goal (offline) Monday, April 29 2013 @ 10:32 PM CDT



achieve_goal 
Hi,
Edward thank you.now i understand that maths questions.

Regular Member
Registered: 09/14/11 Posts: 102



