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 By: achieve_goal (offline)  Thursday, June 13 2013 @ 02:04 AM CDT (Read 717 times)
achieve_goal

Q1. Maths

Q2. A shopkeeper had some markers in red and blue. If 50 red markers
and 25 blue markers were sold each week, there would be 500 red markers
left when all the blue markers were sold. If 25 red markers and 50 blue markers
were sold each week, there would be 800 red markers left when all the blue
markers were sold. How many markers did the shopkeeper have at first?

Regular Member

Registered: 09/14/11
Posts: 102

 By: echeewh (offline)  Thursday, June 13 2013 @ 07:45 AM CDT
echeewh

Hey there,

//
Updated 14/6/13

Q1.

Pls refer to this thread / post entitled "Question on area/perimeter of circles" last posted on 21/12/12. (currently found on page 19 as at 14/6/13).

//

Following pls find my worked solution for your Q2:

Q2.

*** - for alignment purpose

<1st If>

R : B
50 : 25
2 : 1

R |-----|-----|<------------ 500 ------------>|
B |-----|

<2nd If>

R : B
25 : 50
1 : 2

Split the 1 part (p) of B into 2 units (u) as shown; likewise, do the same for the 2 parts of R.

**** <-------------- 800 --------------------->
R |--|--|--|--|<------------ 500 ------------>|
B |--|--|

3u --> 800 - 500 = 300
1u --> 100

Total markers (R + B ) (at first):
6u + 500 --> (6 × 100) + 500 = 600 + 500 = 1100

=========

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: echeewh (offline)  Thursday, June 13 2013 @ 07:41 PM CDT
echeewh

Q1 was Updated on 14/6/13.

Best Regards,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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