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 By: Kuro (offline)  Sunday, June 16 2013 @ 11:24 PM CDT (Read 739 times)
Kuro

Could some help solve the following 2 questions?

Q1. Alice had some apples and bananas.
3/4 of the apples and 6/7 of the bananas are in good condition.
9/11 of the good fruits are apples.
If the number of apples Alice had was 522 more than bananas, how many fruits did Alice have in all?
Ans: 774 fruits

Q2. The figure (in the attachment) is made of a semi circle. a quadrant and a square.
The area of the square is 784 cm2.
Find the total area of the shaded parts.
Ans : 588 cm2

Junior

Registered: 12/31/06
Posts: 27

 By: echeewh (offline)  Monday, June 17 2013 @ 01:21 PM CDT
echeewh

Hey Kuro,

Following pls find my worked solutions:

Q1.

GA : GB
9 : 2

(3/4)A = 9u
(4/4)A = 9u × (4/3) = 12u

(6/7)B = 2u
(7/7)B = 2u × (7/6) = (7/3)u

Given that number of Apples (A) was 522 more than Bananas (B ), we have ...

A - B = 522
12u - (7/3)u = 522
(29/3)u --> 522
1u --> 522 × (3/29) = 54

Total fruits (A + B ) = 12u + (7/3)u
12u + (7/3)u = (43/3)u --> (43/3) × 54 = 774

==========

Q2.

<posted 18/6>

Refer to attachment for my worked solution.

==========

Trust this helps.

Do let me know if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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