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 By: vivilau1112 (offline)  Tuesday, June 25 2013 @ 03:07 AM CDT (Read 649 times)
vivilau1112

Hey everyone!Can someone help me with this question?Thanks in advance.

1.
If Terry gives 30% of his sweets to Alex, they will have the same number of sweets.BUT
If Terry gives 750 of his sweets to Alex, then Alex will have 80% more sweets than Terry.How many sweets does Terry have?

Junior

Registered: 04/13/11
Posts: 16

 By: echeewh (offline)  Tuesday, June 25 2013 @ 04:39 AM CDT
echeewh

Hi vivi,

Following is my worked solution:

Q1.

<after>
T |--------------------|
A |--------------------|

<process>
T: -30% (3/10) of his sweets to A. Left (7/10). Working backwards, add back (3/10) and T's <before> model will have 10 parts. A left with 4 parts.

<before>
T |--|--|--|--|--|--|--|--|--|--|
A |--|--|--|--|

T : A
10 : 4

<process1>
T: -750 to A.

<after1>
T : A
100 : 180
5 : 9

Since this is an Internal Transfer process, apply <Unchanged Total> concept, i.e. total sweets (T + A) <before> = total sweets (T + A) <after1>

Referring to T <before> and <after1> ratio components, we have ...

10u - 5u = 750
5u --> 750
1u --> 150

Hence, T <before> = 10u of sweets
10u --> 10 × 150 = 1500

Terry (T) has 1500 sweets.

========

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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