Hi <kuro>,

Following are my worked solutions:

Q1.

*** - for alignment purpose

<before>

E |------------------------------|

F |-------|

M |-------|-------|

<process>

F: +33

M: -(1/2)M

E: -14

<After>

<---- : decrease

*********************** 14

********* <- 27 --><----------

E |-------------------|<-6->---| {E lost 14, but F had 6 more}

F |-------|<---- 33 ----->|

M |-------|-------|

********* <--------

Given that E,F,M had 150 cards at the end, we have ...

3u + 27 + 33 = 150

3u = 150 - 60 = 90

1u --> 30

At first:

E = 1u + 27 + 14 --> 30 + 41 = **71**

F = 1u --> **30**

M = 2u --> 2 × 30 = **60**

===========

Q2

(3/4)total = (15/20)total (packed in boxes of 4)

(3/5) of remaining = (3/5) × (1/4) = (3/20)total (packed in containers of 6)

Hence, 2u of cupcakes were left.

2u --> 16

1u --> 8

(a)

Boxes of 4:

15u --> 15 × 8 = 120

120 ÷ 4 = 30 boxes

Containers of 6:

3u --> 3 × 8 = 24

24 ÷ 6 = 4 containers

hence, total number of boxes and containers used is **34**.

(b)

Amount sold/earned:

30 boxes = 30 × 10 = $300

4 containers = 4 × 12 = $48

Total amount sold/earned is **$348**

==========

Trust this helps.

Do let me know again if there's further clarifications

Cheers,

Edward