
By: happygolucky (offline) Sunday, July 14 2013 @ 03:27 AM CDT (Read 1265 times)



happygolucky 
Hi
Please help with the following questions. Thanks.
Q27. The ratio of the number of stickers Aaron had to the total number of stickers Benedict and Caleb had was 2:3. The ratio of the number of stickers Benedict had to the total number of stickers Aaron and Caleb had was 4:5. Find the ratio of the number of stickers Aaron had to the number of stickers Benedict had to the number of stickers Caleb had.
Ans : 18:20:7
Q30. Every Saturday, Mabel will go for her usual exercise. If she runs up 32 steps and walks up 68 steps, she will take 184 seconds. If she runs up 50 steps and walks 50 steps, she will take 175 seconds. If she runs at the same rate throughout the whole exercise, how long will she take to run the 100 steps?
Ans : 150
Q6 . Phoebe's annual expenditure is 2/5 less than Chloe's and 1/5 more than Denise. If they spent $34020 in a year altogether, find Denise's monthly expenditure.
Ans : 675
Q17. Nicole received more money than Tricia from their mother. 40% of Tricia's money is $16 less than 25% of Nicole's money. If Nicole gives 35% of her money to Tricia, Nicole will have $12 less than Tricia.
a) How much money does Tricia has?
b) How many per cent more money does Nicole has than Tricia at first? Round off your answers to the nearest 2 decimal places.
Ans: 60, 166.67%

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Registered: 12/31/06 Posts: 2





By: echeewh (offline) Sunday, July 14 2013 @ 07:12 AM CDT



echeewh 
Hi <happygolucky>,
Appreciate that you try to limit the number of questions per post / thread to 2. This will allow us to respond to your questions in a more efficient manner. Thank you.
Following are my worked solutions to Q27 and 30. The rest will follow in due course.
Q27.
**  for alignment purpose
A : (B + C) ** Total
2 : *** 3 ****** 5  (1)
B : (A + C) ** Total
4 : *** 5 ****** 9  (2)
As the total number of stickers A,B,C remains the same in both ratios, we can apply the <Unchanged Total> concept.
Multiply (1) 9x , (2) 5x.
A : (B + C) ** Total
18 : 27 ****** 45  (3)
B : (A + C) ** Total
20 : 25 ****** 45  (4)
Hence, C = 45u  18u  20u = 7u
A : B : C
18 : 20 : 7
=========
Q30.
32R + 68W = 184  (1)
50R + 50W = 175  (2)
Eliminate W by taking the Lowest common multiple (LCM) of 68, 50 is 1700.
(1)x25:
800R + 1700W = 4600  (3)
(2)x34:
1700R + 1700W = 5950  (4)
(4)(3):
1700R  800R = 5950  4600
900R = 1350
R = 3/2
To run the 100 steps,
100R = 100 × (3/2) = 150 secs
=========
Trust this helps.
Do let me know again if there's further clarifications.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 623





By: echeewh (offline) Sunday, July 14 2013 @ 11:18 PM CDT



echeewh 
//
Q6, 17 posted on Jul 15, 12 45
//
Q3.
<Annual Expenditure>
P is (2/5) less than C, i.e. C has 5 parts (p) while P has 3 parts (p).
P is (1/5) more than D, i.e. 3p of D = (6/5).
D = (5/5) = 3p × (5/6) = (5/2)p
So we have the 1p split into 2 units(u) as shown.
P  ***** > 3p × 2 = 6u
C  ***** > 5p × 2 = 10u
D  ***** > (5/2)p × 2 = 5u
Given that total expenditure is $34020, we have ...
6u + 10u + 5u = 34020
21u = 34020
1u > 1620
D (Annual expenditure) = 5u > 5 × 1620 = 8100
Monthly expenditure of D:
8100 ÷ 12 = $675
========
Q17.
***  alignment purpose
40% T = (2/5)T
25% N = (1/4)N
Given that 40% of Tricia's (T) money is $16 less than 25% of Nicole's (N) money, we have ...
(1/4)N  (2/5)T = 16
T  ******* > (2/5)T
N <16> * > (1/4)N
<Before>
T  ***** > 5u
N <16><16><16><16> ***** > 8u + 64
<35% N given to T>
35% N = (7/20)N
(7/20)N = [(7/20) × 8u] + [(7/20) × 64]
= (14/5)u + (112/5)
<After>
T: 5u + (14/5)u + (112/5)
= (39/5)u + (112/5)
N: 8u + 64  (14/5)u  (112/5)
= (26/5)u + (208/5)
T  N = 12
(39/5)u + (112/5)  (26/5)u  (208/5) = 12
(13/5)u = 12  (112/5) + (208/5) = (156/5)
13u > 156
1u > 12
(a)
T (at first) = 5u > 5 × 12 = $60
(b)
N (at first) = 8u + 64
8u + 64 > (8 × 12) + 64 = $160
N  T = 160  60 = 100
% more than T = (100 ÷ 60) × 100 ~ 166.67% (nearest 2 dec places)
========
Let me know again if there's further clarifications.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 623



